Question

Is 5 a solution to the equation 3(x+1)=7(x-2)-3

Answer 1

Answer:

yes

Step-by-step explanation:

3x5=15

3x1=3   15+3=18

7x5=35

7x2=14   35-14=21    21-3=18

18=18

Answer 2

Proof:

Given $3(x+1)=7(x-2)-3$

To prove that the solution of  $3(x+1)=7(x-2)-3$ is 5,

$3(x+1)=7(x-2)-3$

On taking off the brackets we get,

$3x+3=7x-14-3$

On grouping the x terms together,

$7x-3x=14+3+3$

On solving we get,

$4x=20$

$x=\frac{20}{4}$

On dividing 20 by 4,

$x=5$  

$\Rightarrow$ Hence proved that the solution for $\bold3(x+1)=7(x-2)-3\bold$ is 5.