After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.
After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.
And so on. After t years, the investment would have a value of 
.
We want the find the number of years n such that
Solve for n :
1 gallon = 2.93
2 gallons = 5.86
3 gallons = 8.86
Therefore the correct table is D.
The blank is equal to 3/14
Answer:
x = 1 + i sqrt(7/2) or x = 1 - i sqrt(7/2)
Step-by-step explanation:
Solve for x:
2 x^2 - 4 x + 9 = 0
Divide both sides by 2:
x^2 - 2 x + 9/2 = 0
Subtract 9/2 from both sides:
x^2 - 2 x = -9/2
Add 1 to both sides:
x^2 - 2 x + 1 = -7/2
Write the left hand side as a square:
(x - 1)^2 = -7/2
Take the square root of both sides:
x - 1 = i sqrt(7/2) or x - 1 = -i sqrt(7/2)
Add 1 to both sides:
x = 1 + i sqrt(7/2) or x - 1 = -i sqrt(7/2)
Add 1 to both sides:
Answer: x = 1 + i sqrt(7/2) or x = 1 - i sqrt(7/2)
