42.56x10 power of 2=???

hodyreva [135]

1.
{a, e, i, o}
{a} , {e} , {i} , {o} , {a,e} , {a,i} , {a,o} , {e,i} , {e,o} , {i,o} , {a,e,i} , {a,e,o} , {a,i,o}

2.
{0, 1, 2}
{0} , {1} , {2} , {0,1} , {0,2} , {1,2}

3.
Suppose U = {1, 2, 3, 4, 5} is the universal set and A = {2, 3}. What is A ?
Well "A" is {2, 3}, but I'm guessing you meant A'.
A' is all the numbers you don't see, which is
{1, 4, 5}

4.
Suppose U={1, 2, 3, 4, 5, 6, 7, 8} is the universal set and P={2,4, 6, 8}. What is P?
Again, "P" is just {2,4, 6, 8}, but P' is all the numbers you don't see, which are all prime numbers in this sequence:
{1, 3, 5, 7}

5.
-4 < k + 3 < 8
subtract 3 from all sides
-7 < k < 5

6.
 5 <= y + 2 <= 11
subtract 2 from all sides
3 <= y <= 9

7.
6b - 1 < -7 or 2b + 1 > 5
solve both
6b - 1 < -7
add both sides by 1
6b < -6
divide both sides by 6
b < -1

now do the other problem
2b + 1 > 5
subtract both sides by 1
2b > 4
divide both sides by 2
b > 2
answer: b < -1 or b > 2

8.
5 + m > 4 or 7m < -35
subtract both sides by 5 |or| divide both sides by 7
m > -5 or m < -5
m = -5

8 0

4 years ago

Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .

tankabanditka [31]

Answer:

Slope of a tangent to the curve = $f'(x) = \frac{-1 }{(x+1)^{2} }$

Step-by-step explanation:

Given - y = 1/x+1

To find - Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .

Proof -

We know that,

Slope of tangent line = f'(x) = $\lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$

We have,

f(x) = y = $\frac{1}{x+1}$

So,

f(x+h) = $\frac{1}{x+h+1}$

Now,

Slope = f'(x)

And

$f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \\= \lim_{h \to 0} \frac{\frac{1}{x+h+1} - \frac{1}{x+1} }{h}\\= \lim_{h \to 0} \frac{x+1 - (x+h+1) }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{x +1 - x-h-1 }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-h }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-1 }{(x+1)(x+h+1)}\\= \frac{-1 }{(x+1)(x+0+1)}\\= \frac{-1 }{(x+1)(x+1)}\\= \frac{-1 }{(x+1)^{2} }$

∴ we get

Slope of a tangent to the curve = $f'(x) = \frac{-1 }{(x+1)^{2} }$

6 0

3 years ago

the point (x,y) is reflected across the x-axis. Then the new point is reflected across the y-axis. the location of the point ref

natali 33 [55]

This is correct. The x-axis and the y-axis cross each other under a 90 degree angle. This gives us 4 quadrants with different values. The first quadrant is the upper-right (+,+), the second quadrant is, going counter-clockwise, the upper left (-,+), the third quadrant is the lower left (-,-), and the last, fourth one is the lower right (-,+). Positive values on the x-axis are on the right side of the meeting point, and the negative values are on the other side. The positive values on the y-axis are on the upper part. So, if the point is first with two positive values, it means that it is in the 1st quadrant. Moving it across the x-axis would take it in the same position but down, in the 4th quadrant (-,+), and then reflecting it across the y-axis would move it in the same place but left, like in a mirror, and it would place it in the 4th quadrant with two negative values, or -x, -y like the statement.

8 0

3 years ago

I need the quadratic formula.

kvasek [131]

Answer:

ax^2+bx+c=0

Step-by-step explanation:

hope this helps

5 0

4 years ago

Read 2 more answers

What is the exact volume of a cylinder 4" with by 8" length the answers are 32in 64in 128in 512in

Nataly_w [17]

Volume of a cylinder is:

π x radius² x height

Radius = width / 2 = 2

so:

π x 2² x 8 = 32π = 100.53

I'm guessing the answer is "32in" because that's the only answer that matches the answer 32π. Maybe the units are wrong in the question.

5 0

4 years ago