D (you may be unable to link to the site). The site cannot handle the large load of requests and are queued therefore, the response will be slowed down immensely. <span> </span>
Answer:
This is the complete correct program:
#include <stdio.h>
#include<sys/types.h>
#include<unistd.h>
int value = 128;
int main()
{
pid_t pid;
pid=fork();
if (pid==0) /* child process */
{
value +=8;
return 0; }
else if (pid > 0) {/* parent process */
wait (NULL);
printf ("PARENT: value =%d\n" ,value); /* LINEA */
return 0;
}
}
The output of the LINE A is:
PARENT: value = 128
Explanation:
The fork() function used in the program creates a new process and this process is the child process. The child process is same as the original process having its own address space or memory.
In the child process the value of pid is 0. So the if condition checks if pid==0. Then the child process adds 8 to the value of its variable according to the following statement
value +=8;
Now the original process has value = 128. In else if part the parents process has the value of pid greater than zero and this portion of the program is of the parent process :
else if (pid > 0)
{ wait (NULL);
printf ("PARENT: value =%d\n" ,value);
return 0; }
So the value 128 is printed at the end in the output.
wait(NULL) is used to wait for the child process to terminate so the parent process waits untill child process completes.
So the conclusion is that even if the value of the variable pid is changed in the child process but it will not affect the value in the variable of the parent process.
<span>Images are available in many formats, such as tif, bmp, gif, jpeg, and png.
</span>Hope that helps.
The two main
capabilities involved in visual literacy are:
<span>1) </span>Communication through use of visual elements.
<span>2) </span>Interpret meaning from visual elements.
<span>Visual literacy is the
capacity to decipher, arrange, and make significance from data displayed as a
picture, broadening the importance of proficiency, which means understanding of
a composed or printed content.</span>
Explanation:
Here if the value in the register $f2 is equals to the value in $f4, it jumps to the Label1. If it should jump when the value in the register $f2 is NOT equals to the value in $f4, then it should be
