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3 years ago

Find the coordinates of the point(s on the curve 2y=10?x2 that are closest to the origin

Mathematics

1 answer:

sergey [27]3 years ago

4 0

No it far 10 is way out there

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Please solve! Thx! 6 = 20 - 3x

kumpel [21]

Answer:

Step-by-step explanation:

6=20-3x

combine

6-20=-3x

-14 = -3x

divide by -3

-14/-3 = -3x/-3

x = 4.666 repeatedly

x = 5 approximately

5 0

3 years ago

In a large population, 57 % of the people have been vaccinated. If 3 people are randomly selected, what is the probability that

ollegr [7]

Answer:0.92

Step-by-step explanation:

Given

$57\%$ of Population is vaccinated

So, Probability of a person being vaccinated is $P=0.57$

and simultaneously , probability of not vaccinated is $1-P$

$=1-0.57=0.43$

Now, Probability that atleast one of them has been vaccinated is given by

$=1-P(\text{None of them is vaccinated})$

$=1-0.43\times 0.43\times 0.43$

$=1-0.0795$

$=0.92$

7 0

3 years ago

Read 2 more answers

Answer this and I’ll make you Brainly

snow_tiger [21]

Step-by-step explanation:

Option A is the correct answer

f(x)=8x+2

put x=-4

then out =8(-4)+2 = -32+2= -30

6 0

2 years ago

In 2000, the population of a county was 25,300,987. The population decreased at a rate of 2% each year. What was the population

EastWind [94]

Answer: In 2008 the population was 21,525,144

Step-by-step explanation:

You need to use the following formula for Exponential decay:

$P=P_0(1-r)^t$

Where $P_0$ is the initial population in the year 0, $r$ is the rate of decay and $t$ is the time.

In this case, you can identify that:

$P_0=25,300,987\\\\r=2\%\\\\t=8$

Therefore, substituting these values into the formula for Exponential decay, you get:

$P=P_0(1-r)^t\\\\P=(25,300,987)(1-\frac{2}{100})^8\\\\P=21,525,144$

Then, in 2008 the population was 21,525,144

6 0

2 years ago

Find the value of x.

grandymaker [24]

I think X is 2. But I am not sure, cuz I don’t know what you teacher is really asking you to do.

8 0

2 years ago