Question

Which sine ratios are correct for ΔPQR? Check all that apply.

Answer 1

Answer:

Sin(P)=p/q

Sin(R)=r/q

Step-by-step explanation:

The given question is INCOMPLETE.

which sine ratios are correct for ∆PQR? Check all that apply

sin(p)=r/q

sin(p)=p/q

sin(q)=r/p

sin(r)=q/r

sin(r)=r/q​

Now, as we know in any right angled triangle:

$Sin (\theta) = \frac{Perpendicular}{Hypotenuse}$

Now, here in ∆PQR

If we consider angle P, then QR  = p is Perpendicular.

$Sin (P) = \frac{Perpendicular}{Hypotenuse} = \frac{p}{q}$

If we consider angle R, then PQ  =  r is Perpendicular.

$Sin (R) = \frac{Perpendicular}{Hypotenuse} = \frac{r}{q}$

Hence,   sin(p)=p/q  and sin(r)=r/q are the ONLY correct options.