C. Dominant
The trait would be heterozygous which means one dominant allele and one recessive allele but the dominant allele always over powers the recessive allele
Answer:
A population ecologist uses many terms while writing his case study. Match each term to its definition.
an indication of the number of individuals of a population and the area that they occupy
population density
an increase in the number of individuals of a species over a period of time, expressed as a percentage
growth rate
the number of live births per 1,000 organisms of a species in a year
Birth rate
the number of deaths per 1,000 organisms of a species in a year
death rate
Explanation:
Answer:
Nutritive and varied stimulus exposure divergence
Explanation:
No doubt that Human and Eyes of fly have Pax6 conserved sequences and their primary function is highly conserved.but there is a very simple explanation for their morphological divergence. First divergence takes place where flies have totally different stimulus exposure and that continuous exposure develops a more suitable hexagonal facets by evolutionary point of view are necessary for quick motion detection. Although they can only differ between bright and dark, they don't provide a very pure vision but this is necessary for them. The ectopic expression can be explained by their different nutritive exposure over the course of their evolution.
Answer:
1/64
Explanation:
<em>The probability of the offspring being homozygous dominant for the three alleles is 1/64.</em>
Since the three characters assort independently, the probability of the offspring being homozygous dominant for all the three traits is an independent event.
For independent events, the probability of all the events happening together is the multiplication of individual event's probability.
For a cross involving two heterozygotes, taking tall/dwarf for example:
Tt x Tt = TT, 2Tt, tt
The probability of obtaining a homozygous dominant genotype is 1/4.
Hence, the probability of the offspring being homozygous dominant for the three alleles will be:
1/4 x 1/4 x 1/4 = 1/64