The required solution to the trigonometry equation is x = π/4 + π n.
The equation of trigonometry functions is given in the question as
secx - cscx = 0
We have to determine the solution to the given equation
As per the question, we have
⇒ secx - cscx = 0
⇒ 1/cosx - 1/sinx = 0
⇒ (-cosx + sinx)/cosxsinx = 0
Using property : f(x)/g(x) = 0 ⇒ f(x) = 0
⇒ -cosx + sinx = 0
Divided by cosx into the equation,
⇒ -1 + tanx = 0
⇒ tanx = 1
The general solution for tan tanx = 1 is
⇒ x = π/4 + π n
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Answer:
Rider A 450 Rider B 360
Step-by-step explanation:
Answer:
i think you would multiply them but I'm not sure
The function is written as:
f(x) = log(-20x + 12√x)
To find the maximum value, differentiate the equation in terms of x, then equate it to zero. The solution is as follows.
The formula for differentiation would be:
d(log u)/dx = du/u ln(10)
Thus,
d/dx = (-20 + 6/√x)/(-20x + 12√x)(ln 10) = 0
-20 + 6/√x = 0
6/√x = 20
x = (6/20)² = 9/100
Thus,
f(x) = log(-20(9/100)+ 12√(9/100)) = 0.2553
<em>The maximum value of the function is 0.2553.</em>
The answer is D.122 BC is the square root of 22 squared and 120 squared.
