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murzikaleks [220]
3 years ago
8

A school principal trying to find out if parents will help buy new playground equipment shows digital leadership by.

Computers and Technology
2 answers:
ELEN [110]3 years ago
8 0

Answer:

D. is the correct answer!

mr Goodwill [35]3 years ago
8 0

Answer:

B. Creating a email survey for parents

Explanation:

I did this on edg

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Write a program that plays the popular scissor-rockpaper game. (A scissor can cut a paper, a rock can knock a scissor, and a pap
kolbaska11 [484]

Answer:

import random

computer = random.randint(0, 2)

user = int(input("scissor (0), rock (1), paper (2): "))

if computer == 0:

   if user == 0:

       print("The computer is scissor. You are scissor too. It is a draw")

   elif user == 1:

       print("The computer is scissor. You are rock. You won")

   elif user == 2:

       print("The computer is scissor. You are paper. Computer won")

elif computer == 1:

   if user == 0:

       print("The computer is rock. You are scissor. Computer won")

   elif user == 1:

       print("The computer is rock. You are rock too. It is a draw")

   elif user == 2:

       print("The computer is rock. You are paper. You won")

elif computer == 2:

   if user == 0:

       print("The computer is paper. You are scissor. You won")

   elif user == 1:

       print("The computer is paper. You are rock. Computer won")

   elif user == 2:

       print("The computer is paper. You are paper too. It is a draw")

Explanation:

*The code is in Python.

Import the random to be able to generate number number

Generate a random number between 0 and 2 (inclusive) using randint() method and set it to the computer variable

Ask the user to enter a number and set it to the user variable

Check the value of computer the computer variable:

If it is 0, check the value of user variable. If user is 0, it is a draw. If user is 1, user wins. If user is 2, computer wins

If it is 1, check the value of user variable. If user is 0, computer wins. If user is 1, it is a draw. If user is 2, user wins

If it is 2, check the value of user variable. If user is 0, user wins. If user is 1, computer wins. If user is 2, it is a draw

8 0
2 years ago
Who does car shows in gta 5 or what do you guys do in gta
grandymaker [24]

Answer:

google can find u some discord servers

Explanation:

4 0
3 years ago
Read 2 more answers
write (define) a public static method named countup, that takes one int argument and returns no value. you can safely assume tha
tester [92]

Using the knowledge of computational language in python it is possible to write a code that write (define) a public static method named countup, that takes one int argument and returns no value.

<h3>Writting the code:</h3>

<em>public class </em><em>Main</em>

<em>{</em>

<em>public static void main(</em><em>String</em><em>[] args) {</em>

<em>// testing the method </em><em>countDown </em><em>with values 5, 6, 1</em>

<em>countDown(5);</em>

<em>System.out.println();</em>

<em>countDown(6);</em>

<em>System.out.println();</em>

<em>countDown(2);</em>

<em>System.out.println();</em>

<em>}</em>

<em />

<em>public static void </em><em>countDown</em><em>(int num)</em>

<em>{</em>

<em>for (int i=1 ; i<=num ; i++) // for </em><em>loop </em><em>iterates from 1 to num</em>

<em>{</em>

<em>System.out.print(i+","); // prints num followed by comma ,</em>

<em>}</em>

<em>}</em>

<em>}</em>

See more about JAVA at brainly.com/question/12975450

#SPJ1

7 0
1 year ago
To ensure proper seating of the valve, the valve seat must be
Marta_Voda [28]
The vaule must be set true not false
5 0
2 years ago
True or false: offset printing has more expensive start up costs than than a digital printing system
denis-greek [22]

True Offset printing is more expensive.

Offset printing often has a longer turnaround and is more expensive to set up, so that for short print runs, the cost per unit is higher than digital printing.

5 0
3 years ago
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