Question

PLEASE HELP!!

Answer 1

All these cases represent experiments whose outcomes are all equaly likely. What we mean is that the cards have all the same probability of being dealt (1/52), and all the spaces of the spinner have the same probability of being landed into (1/5).

These probabilities are computed as 1 over all the possible outcomes.

(a) If you want a heart card and a five, you want the 5 of hearts. So, only one card would satisfy your request, and thus you have probability 1/52 of dealing the 5 of hearts.

$\dfrac{1}{52}\approx 0.019 = 1.9\%$

(b) There are four 10s and four Jacks in the deck, so 8 cards satisfy your request. With probability 8/52, you'll be dealt a Jack or a 10.

$\dfrac{8}{52}=\dfrac{2}{13}\approx 0.154 = 15.4\%$

(c) You have two "good" outcomes out of 5, so your probability is 2/5.

$\dfrac{2}{5}=0.4=40\%$