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Mkey [24]
4 years ago
12

During a football game, a receiver has just caught a pass and is standing still. Before he can move, a tackler, running at a vel

ocity of 3.40 m/s, grabs and holds onto him so that they move off together with a velocity of 1.70 m/s. If the mass of the tackler is 133 kg, determine the mass of the receiver. Assume momentum is conserved.
Physics
1 answer:
Nata [24]4 years ago
4 0

Answer:

133 kg

Explanation:

Parameters given:

Mass of tackler, m = 133 kg

Initial velocity of tackler, u = 3.4 m/s

Final velocity of tackler and receiver, v = 1.7 m/s

Since momentum is conserved, we apply the principle of conservation of momentum:

Total initial momentum = Total final momentum

mu + MU = (m + M)v

Where U = initial velocity of receiver = 0 m/s

M = mass of receiver

Therefore:

(133 * 3.4) + (M * 0) = (133 + M) * 1.7

452.2 = (133 + M) * 1.7

(133 + M) = 452.2/1.7

133 + M = 266

=> M = 266 - 133

M = 133 kg

The mass of the receiver is 133 kg.

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4 0
3 years ago
A ball on the end of a string is revolving at a uniform rate in a vertical circle of radius 97.7 cm. If its speed is 3.74 m/s, a
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The tension in the string when the ball is at the bottom of the path is 2.61 Newtons.

<h3>Tension</h3>

A tension is simply referred to as a force along the length of a flexible medium such as strings, cable, ropes etc.

Tension in a string revolving can be determined using the expression;

T = mv² / r

Where m is mass of object, v is velocity and r is radius ( length of string )

Given the data in the question;

  • Mass of ball m = 0.182kg
  • Radius ( length of string ) r = 97.7cm = 0.977m
  • Velocity = 3.74m/s
  • Tension in the string; T = ?

To determine tension in the string, we substitute our given values into the expression above.

T = mv² / r

T = (0.182kg × (3.74m/s)²) / 0.977m

T = (0.182kg × 13.9876m²/s²) / 0.977m

T = (2.5457432kgm²/s²) / 0.977m

T = 2.61kgm/s²

T = 2.61N

Therefore, the tension in the string when the ball is at the bottom of the path is 2.61 Newtons.

Learn more about Tension here: brainly.com/question/14351325

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2 years ago
What is the farthest distance at which a typical "nearsighted" frog can see clearly in air?
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Answer: the correct option is D (17m).

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4 years ago
Calculate the hydrostatic difference in blood pressure between the brain and the foot in a person of height 1.93 m. The density
Slav-nsk [51]

Answer:

Explanation:

Given: Density of blood = 1.03 × 10³ Kg/m³, Height =  1.93 m g = 9.8 m/s²

pressure at the brain is equal to atmospheric pressure. = Hydro-static

pressure(ρ₀)

∴ pressure of the foot = pressure of the brain(ρ₀) + ( density of blood × acceleration due to gravity × height)(ρgh)

Hydro-static pressure = pressure at the feet- pressure at the brain(ρ₀)

Hydro-static pressure (Δp) = (ρgh + ρ₀) - ρ₀ = ρgh

Hydro-static pressure = 1.03 × 10³ × 9.8 × 1.93 = 1.948 × 10⁴ Pa

∴  Hydro-static pressure ≈ 1.95 × 10⁴ Pa

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3 years ago
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