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Mkey [24]
4 years ago
12

During a football game, a receiver has just caught a pass and is standing still. Before he can move, a tackler, running at a vel

ocity of 3.40 m/s, grabs and holds onto him so that they move off together with a velocity of 1.70 m/s. If the mass of the tackler is 133 kg, determine the mass of the receiver. Assume momentum is conserved.
Physics
1 answer:
Nata [24]4 years ago
4 0

Answer:

133 kg

Explanation:

Parameters given:

Mass of tackler, m = 133 kg

Initial velocity of tackler, u = 3.4 m/s

Final velocity of tackler and receiver, v = 1.7 m/s

Since momentum is conserved, we apply the principle of conservation of momentum:

Total initial momentum = Total final momentum

mu + MU = (m + M)v

Where U = initial velocity of receiver = 0 m/s

M = mass of receiver

Therefore:

(133 * 3.4) + (M * 0) = (133 + M) * 1.7

452.2 = (133 + M) * 1.7

(133 + M) = 452.2/1.7

133 + M = 266

=> M = 266 - 133

M = 133 kg

The mass of the receiver is 133 kg.

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The springs of a 1500 kg car compress 5.00 mm when its 68 kg driver gets into the driver's seat. Part A If the car goes over a b
elena-s [515]

Answer:

the frequency of the oscillation is 1.5 Hz

Explanation:

Given;

mass of the spring, m = 1500 kg

extention of the spring, x = 5 mm = 5 x 10⁻³ m

mass of the driver = 68 kg

The weight of the driver is calculated as;

F = mg

F = 68 x 9.8 = 666.4 N

The spring constant, k, is calculated as;

k = F/m

k = (666.4 N) / (5 x 10⁻³ m)

k = 133,280 N/m

The angular speed of the spring is calculated;

\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{133280}{1500} } = 9.426 \ rad/s

The frequency of the oscillation is calculated as;

ω = 2πf

f = ω / 2π

f = (9.426) / (2π)

f = 1.5 Hz

Therefore, the frequency of the oscillation is 1.5 Hz

6 0
3 years ago
A resistor with r = 340 ω and an inductor are connected in series across an ac source that has voltage amplitude 490 v. The rate
Arada [10]

The value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.

<h3>What is impedance Z of the circuit?</h3>

The impedance Z of the circuit is the ratio of voltage amplitude to the maximum current.

Z=\dfrac{V}{I}

Here, <em>V </em>is voltage amplitude and<em> I</em> maximum current.

A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 490V. The rate at which electrical energy is dissipated in the resistor is 316 W.

The rate at which electrical energy is dissipated in the resistor is the product of the resistance and the square of current. Thus,

316=340\times I^2\\I=\sqrt{\dfrac{316}{340}}\\I=0.964\rm\; A

The impedance Z of the circuit is,

Z=\dfrac{V}{I}\\Z=\dfrac{490}{0.964}\\Z=508\rm\; ohm

Thus, the value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.

Learn more about the impedance Z of the circuit here:

brainly.com/question/24225360

#SPJ4

5 0
2 years ago
Which item is an example of a primary source? A. An academic paper analyzing John F. Kennedy's presidency B. A transcript of a p
Viktor [21]

A transcript of a presidential speech (APEX Class ;)

7 0
3 years ago
What gravitational force does the moon produce
saul85 [17]

Answer:

1.94\cdot 10^{20} N

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

The gravitational force is always attractive.

In this problem, we have:

m_1 = 5.98\cdot 10^{24}kg is the mass of the Earth

m_2 = 7.34\cdot 10^{22} kg is the mass of the Moon

r=3.88\cdot 10^8 m is the separation between the Earth and the Moon

Therefore, the gravitational force between them is

F=(6.67\cdot 10^{-11})\frac{(5.98\cdot 10^{24})(7.34\cdot 10^{22})}{(3.88\cdot 10^8)^2}=1.94\cdot 10^{20} N

6 0
3 years ago
¿Cuál es la masa aproximada del aire en una habitación de 5.6 m * 3.8 m * 2.8 m?
Nady [450]
It would be 3.15 in meters
8 0
3 years ago
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