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aksik [14]
3 years ago
6

PLEASE HELP WITH MATH!

Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0
I will be glad to help you in the comments. I do need to know though, what is the class this is presented in? Is this algebra, or calculus? Depending on the class, we have different approaches.
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X=0 is the correct answer
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Determine the value of X
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180-105=75

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Ron talked on the phone for 1/5 an hour. Jacob talked on the phone for 1/100 a day. Who talked longer on the phone?
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Testing for a disease can be made more efficient by combining samples. If the samples from four people are combined and the mixt
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Answer:

There is a 34.39% probability of a positive result for four samples combined into one mixture.

This probability is not low enough so that further testing of the individual samples is rarely​ necessary,

Step-by-step explanation:

There are only two possible outcomes. Either a sample tests positive, or it does not, so we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A number of sucesses x is considered unusually low if P(X \leq x) \leq 0.05 and unusually high if P(X \geq x) \geq 0.05

In this problem, we have that:

There are four samples, so n = 4

Each sample has a probability of 0.1 of being positive, so \pi = 0.1.

Assuming the probability of a single sample testing positive is 0.1​, find the probability of a positive result for four samples combined into one mixture.

If any sample is positive, the result of the four samples is positive. So this is P(X>0). Either the number of positive samples is 0, or it is greater than 0. The sum of the probabilities is decimal 1. So:

P(X = 0) + P(X>0) = 1

P(X>0) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{4,0}.(0.10)^{0}.(0.9)^{4} = 0.6561

P(X>0) = 1 - P(X = 0) = 1 - 0.6561 = 0.3439

There is a 34.39% probability of a positive result for four samples combined into one mixture.

This probability if larger than 5%, so it is not low enough so that further testing of the individual samples is rarely​ necessary.

4 0
4 years ago
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