Evaluate the expression. -6+3(-3+7).

Mathematics

2 answers:

Helen [10]3 years ago

6 0

The answer to this would be 6

lesantik [10]3 years ago

3 0

Answer:

answer for this question is 6

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A square has a side length of 7 centimeters. A circle has a diameter of 7 centimeters. What is true about the areas of the two f

Stels [109]

Answer: The area of the circle will be eleven-fourteenth of the area of square.

Step-by-step explanation: Given that a square has a side of length 7 cm and a circle has a diameter of 7 cm. We need to find the statement which is true about the areas of these two figures.

The area of the square will be

$S_a=7^2=49~\textup{cm}^2.$

And, the area of the circle will be

$C_a=\pi r^2=\pi \times \left(\dfrac{7}{2}\right)^2=\dfrac{\pi}{4}\times 49=\dfrac{22}{7\times 4}\times 49\\\\\Rightarrow C_a=\dfrac{11}{14}\times S_a.$

Thus, the area of the circle will be eleven-fourteenth of the areq of the square.

6 0

3 years ago

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A particle moves on the circle x2 y2=25 in the xy-plane for time t≥0. At the time when the particle is at the point (3,4), dxdt=

stiks02 [169]

The movement of the particle on the circle is its displacement.

The value of dy/dt at this time is -9/2.

<h3>What is the differentiation?</h3>

Differentiation is a process, in Maths, where we find the instantaneous rate of change in function based on one of its variables.

A particle moves on the circle x^2 + y^2=25 in the XY-plane for time t≥0. At the time when the particle is at the point (3,4), dxdt=6.

The equation of the circle is given as:

$\rm x^2 + y^2=25$

Differentiate with respect to time

$\rm 2x \times \dfrac{dx}{dt}+2y \times \dfrac{dy}{dt}=0$

Substitute all the values in the equation

$\rm 2x \times \dfrac{dx}{dt}+2y \times \dfrac{dy}{dt}=0\\\\2(3) \times 6+2(4)\times \dfrac{dy}{dt}=0\\\\ 6 \times 6+8 \times \dfrac{dy}{dt}=0\\\\ 36+8\times \dfrac{dy}{dt}=0\\\\ 8\times \dfrac{dy}{dt}=-36\\\\ \dfrac{dy}{dt}= \dfrac{-36}{8}\\\\ \dfrac{dy}{dt}= \dfrac{-9}{2}$