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3 years ago

7

A teacher was making identical activity packets using 92 crayons and 23 sheets of paper. What is the greatest number of packets

the teacher can make with no items left over?

1 answer:

dmitriy555 [2]3 years ago

4 0

Answer:

the teacher can make 23 packets with 4 crayons in each packet

Step-by-step explanation:

the teacher can make 23 packets with 4 crayons in each packet wit no left over.

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7.3×9.6 show your work

Alex_Xolod [135]

1
7.3
x 9.6
-------
438
+ 647 0
69. 0 8, hope that helped

6 0

3 years ago

What’s the 5th term is 2,14,98

iragen [17]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

$\sf{ 2 , 14 ,.... 98 }$
<u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

$\sf{a1\: or \:1st\: term = 2 }$
$\sf{a2 \:or \:2nd\: term = 14 }$
$\sf{an \:or\: last\: term = 98}$

<u>Here</u><u>, </u>

Common difference of an AP

$\sf{ a2 - a1 }$

$\sf{ = 14 - 2}$

$\sf{ = 12}$

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

$\sf{an = a1 + ( n - 1 )d}$

$\sf{a5 = 2 + ( 5 - 1 )12}$

$\sf{a5 = 2 + 4 × 12}$

$\sf{a5 = 2 + 48}$

$\sf{\red{a5 = 50}}$

Hence, The 5th term of given AP is 50

4 0

2 years ago

An isosceles triangle has an angle that measures 94º. Which other angles could be in that

Nataly [62]

Answer:

43°

Step-by-step explanation:

In a isosceles triangle, two angles HAVE to be equal.

This means that 94 can be one of the angles that are equal, or the angle that is not equal to another angle.

Let's start with the fact that 94 can be one of the angles that are equal. (Note: angles in a triangle add up to 180)

94+94+x=180

188+x=180

There is NOT a possible value for x in this situation, as you cannot have a negative value of an angle. Therefore we must try the other situation where 94 is the angle that is not equal to another angle.

x+x+94=180

2x+94=180

Subtract 94 from both sides

2x=86

Divide both sides by 2

x=43

Therefore the answer is 43°

4 0

2 years ago

Find the missing number.<br><br>32/52 = ?/ 13<br><br>A: 9<br>B: 4<br>C: 7<br>D: 8

Dmitry [639]

`The missing number is D 8 32/52=0.61....

8/13=0.61....

Hope this helps

6 0

4 years ago

Suppose you have a random variable that is uniformly distributed between 7 and 26. what is the expected value for this random va

Daniel [21]

$\mathbb E(X)=\int_7^{26}\dfracx{26-7}\,\mathrm dx=\dfrac{33}2=16.5$

which follows from the definition for expected value,

$\mathbb E(X)=\int_{-\infty}^\infty xf_X(x)\,\mathrm dx$

where $f_X(x)$ is the probability density function for $X$ .

4 0

4 years ago