Answer: She would have to work 7 hours to earn $260.
Step-by-step explanation: 40×7=280 280-20=260 Hope this helps.
Complete question :
Birth Month Frequency
January-March 67
April-June 56
July-September 30
October-December 37
Answer:
Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.
Step-by-step explanation:
Observed value, O
Mean value, E
The test statistic :
χ² = (O - E)² / E
E = Σx / n = (67+56+30+37)/4 = 47.5
χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295
Degree of freedom = (Number of categories - 1) = 4 - 1 = 3
Using the Pvalue from Chisquare calculator :
χ² (18.295 ; df = 3) = 0.00038
Since the obtained Pvalue is so small ;
P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.
By geometrical inspection we have:
M4 = 30
Then the angle M6 can be determined from the fact that you have a rectangle triangle (345) that has an angle of 90 and another of 30. The missing angle measures:
180-90-30 = 60 = M3
Then to find M6 we have
M3 + 60 + M6 = 180
M6 = 180-60-M3
M6 = 180-60-60
M6 = 60
answer:
M4 = 30
M6 = 60
It would be y=8x+2/3
Explanation:
Y=|3/4x| is an absolute value
Y=x^3+8 is quadratic
Y=8+5/6x^2 is also quadratic (you can tell it’s quadratic because it has an exponent)
