Well, I don't know. Let's see . . . . .
First draw: One 'M' available out of 11 letters. Probability of picking it = 1/11.
2nd draw: Four 'I's available out of 10 letters. Probability of picking one = 4/10.
3rd draw: Four 'S's available out of 9 letters. Probability of picking one = 4/9.
4th draw: Three 'S's available out of 8 letters. Probability of picking one = 3/8.
5th draw: Three 'I's available out of 7 letters. Probability of picking one = 3/7.
6th draw: Two 'S's available out of 6 letters. Probability of picking one = 2/6.
7th draw: One 'S' available out of 5 letters. Probability of picking it = 1/5.
8th draw: Two 'I's available out of 4 letters. Probability of picking it = 2/4.
9th draw: Two 'P's available out of 3 letters. Probability of picking one = 2/3.
10th draw: One 'P' available out of 2 letters. Probability of picking it = 1/2.
11th draw: One letter left. It is an 'I'. Probability of picking it = 1 .
Probability of all of those draws in order =
(1/11) x (4/10) x (4/9) x (3/8) x (3/7) x (2/6) x (1/5) x (2/4) x (2/3) x (1/2) x (1) =
1,152 / 39,916,800 =
1 / 34,650 =
0.00002886 =
<em> 0.002886 percent</em> (rounded)
Not a good bet. (But better than the lottery.)
Answer:
x = 108°
Step-by-step explanation:
x + 2/3 x = 180°
1 2/3x = 180°
5/3 x = 180°
180 * x = 540
540 / 5 = 108
x = 108°
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Among the choices the one that would be considered a valid measure of an individual's intelligence is <span>the number of years of school that the individual has completed</span>
Solution:
Number of babies which are female = 50%=
So, if Population of 50 is considered , and 50% of population is female then out of 25 must be female.
Population of female can't exceed 25.
Probability of an event = 
Probability that 20 or more of the 50 babies born today were female
= ![_{20}^{50}\textrm{C}\times [\frac{1}{2}]^{20} \times [\frac{1}{2}]^{30}+_{21}^{50}\textrm{C}\times [\frac{1}{2}]^{21} \times [\frac{1}{2}]^{29}+_{22}^{50}\textrm{C}\times [\frac{1}{2}]^{22} \times [\frac{1}{2}]^{28}+_{23}^{50}\textrm{C}\times [\frac{1}{2}]^{23} \times [\frac{1}{2}]^{27}+_{24}^{50}\textrm{C}\times [\frac{1}{2}]^{24} \times [\frac{1}{2}]^{26}+ _{25}^{50}\textrm{C}\times [\frac{1}{2}]^{25} \times [\frac{1}{2}]^{25}](https://tex.z-dn.net/?f=_%7B20%7D%5E%7B50%7D%5Ctextrm%7BC%7D%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B20%7D%20%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B30%7D%2B_%7B21%7D%5E%7B50%7D%5Ctextrm%7BC%7D%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B21%7D%20%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B29%7D%2B_%7B22%7D%5E%7B50%7D%5Ctextrm%7BC%7D%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B22%7D%20%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B28%7D%2B_%7B23%7D%5E%7B50%7D%5Ctextrm%7BC%7D%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B23%7D%20%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B27%7D%2B_%7B24%7D%5E%7B50%7D%5Ctextrm%7BC%7D%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B24%7D%20%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B26%7D%2B%20_%7B25%7D%5E%7B50%7D%5Ctextrm%7BC%7D%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B25%7D%20%5Ctimes%20%5B%5Cfrac%7B1%7D%7B2%7D%5D%5E%7B25%7D)
Simulation of the Above Situation
If we use a double sided coin and a sign heads us females and Tails as males,Toss the coin 50 times , number of times Heads comes shows number of females born and number of times tails appears shows Population of men.
It may not happen that Number of heads =Number of tails if we toss the coin 50 times.So if number of tosses increases the chances are more likely that , number of heads= Number of tails. But for above problem we just have to toss coin 50 times only, that is
Number of males = Number of females
