Question

Write the first five terms of the sequence in which the nth term is an=(n+1)! / n+1

Answer 1

Answer:

1, 2, 6, 24, 120

Step-by-step explanation:

let's work on each of the five terms requested for the sequence. Notice that the first term is when we give n the value 1 $a_1=(1+1)!/(1+1)=2!/2=2/2=1$

Next term (when n=2) is: $a_1=(2+1)!/(2+1)=3!/3=3*2/3=2$

Next term (when n=3) is:  $a_1=(3+1)!/(3+1)=4!/4=4*3*2/4=6$

Next term (when n=4) is:  $a_1=(4+1)!/(4+1)=5!/5=5*4*3*2/5=24$

Next term (when n=5) is:  $a_1=(5+1)!/(5+1)=6!/6=6*5*4*3*2/6=120$