Answer:
ΔABC is not a right- angled triangle
Step-by-step explanation:
Given AB = 8, BC = 5
Then AC = 22 - (8 + 5) = 22 - 13 = 9 cm
Using the converse of Pythagoras' identity
If the square of the longest side equals the sum of the squares of the other 2 sides then triangle is right.
AC² = 9² = 81
AB² + BC² = 8² + 5² = 64 + 25 = 89
81 ≠ 89, hence ΔABC is not right- angled
