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2 years ago

This is for my Precalculus teacher and I am kinda confuse, help please!!

Mathematics

1 answer:

Andrews [41]2 years ago

6 0

Answer:

They are different

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Can someone help me please.

BabaBlast [244]

Answer:

B, or second answer choice

Step-by-step explanation:

y - $y_{1}$ = m(x - $x_{1}$ )

y - 1/3 = 3/4 (x - 4)

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2 years ago

What is the area of this triangle?

fredd [130]

Answer:

i think it's 16

Step-by-step explanation:

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3 years ago

Read 2 more answers

Which expression is not equivalent to others? Explain.

slega [8]

B. This is the answer because it is not equivalent to anything else, and the answer simplified is: -18.

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2 years ago

Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%

BaLLatris [955]

We're looking for an integrating factor $\mu(x,y)=x^py^q$ such that

$\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0$

is exact, which would require that

$(\mu M)_y=(\mu N)_x$
$(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x$
$49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q$
$\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4$

You can verify that $(\mu M)_y=(\mu N)_x$ if you'd like. With the ODE now exact, we have a solution $F(x,y)=C$ such that

$F_x=\mu M$
$F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx$
$F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)$

$F_y=\mu N$
$50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4$
$f'(y)=0$
$\implies f(y)=C$

and so the general solution is

$F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C$

8 0

3 years ago

You have a job earning $12.50 per hour, and you receive a raise so that you earn $13.25 per hour. What is the percent change in

Vlad1618 [11]

$increase = 13.25 - 12.50 \\ increase = 0.75 \: dollars$

$12.50 = 100\% \\ 0.75 = x\%$

$12.50x = 100(0.75) \\ x = \frac{100(0.75)}{12.50} = \frac{75}{12.5} = 6\%$

4 0

2 years ago