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Marta_Voda [28]
3 years ago
13

This is for my Precalculus teacher and I am kinda confuse, help please!!

Mathematics
1 answer:
Andrews [41]3 years ago
6 0

Answer:

They are different

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Are theses 3 answers right?
sweet [91]
Yes they are correct.

At least I'm pretty sure they are:)
6 0
4 years ago
Help me with 3, and 5 show your work !
ss7ja [257]
Okay so for number 3, you have to do the top work first.

3: POSITIVE 2!! first, you do the stuff inside the parentheses first because of P(parentheses)EMDAS. so, 14-2-10! -2-10 is -12 and then plus positive 14 is +2. but, the negative sign outside of the parentheses makes that +2 a -2.
but, you cant forget the -12 outside. you have to do -12-2 which gets you -14. then, this is easy! -14 divided by -7 is a positive 2!

5: POSITIVE 3!! again, do the stuff in the parentheses first!! -2-4 is -6. then, -6 x 2 is -12! so, divide -12 by -4 and you get a positive 3!
5 0
3 years ago
Which set of points is a function?
topjm [15]
B. Cannot have 2 y points on the same x point. Confirm with the vertical line test.
7 0
3 years ago
The table show the age in years of employees in a company
adelina 88 [10]

Answer:

A. 24 ≤ a < 26.

B. 22.5

Step-by-step explanation:

A. Determination of the modal class interval.

Mode is the class with the highest frequency.

From the table given above, the highest frequency is 8, therefore the class will the highest frequency is:

24 ≤ a < 26.

B. To obtain the mean, we must determine the class mark. This is illustrated below:

Class >>>>> class mark >>> frequency

18 – 19 >>>> 18.5 >>>>>>>>> 3

20 – 21 >>> 20.5 >>>>>>>> 2

22 – 23 >>> 22.5 >>>>>>>> 7

24 – 25 >>> 24.5 >>>>>>>> 8

26 >>>>>>>> 26 >>>>>>>>> 0

The mean is given by the summation of the product of the class mark and frequency divided by the total frequency. This is illustrated below:

Mean = [(18.5x3) + (20.5x2) + (22.5x7) + (24.5x8) + (26x0)] / (3+2+7+8+0)

Mean = (55.5 + 41 + 157.5 + 196 + 0)/20

Mean = 450/20

Mean = 22.5

Therefore, the mean age is 22.5

4 0
3 years ago
Read 2 more answers
एउटा आयताकार चाउरको परिमिति 1004 m भए सो चउरको
frez [133]

Answer:

502m

Step-by-step explanation:

let x and y represent the length and breadth of rectangular meadow respectively.

Given,

Perimeter of the meadow =1004m

or,2(l+b)=1004m

or2(x+y)=1004m

orx+y=1004m/2

or,x+y=502m

i.e sum of length and breadth

5 0
3 years ago
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