7 units to the right of -4

How many students were questioned about the approximate number of text messages they send each day? Explain or

d1i1m1o1n [39]

Do you have anymore information that doesn’t help that much

3 0

3 years ago

You buy 1 1/4 yards of fabric and $8 clothing pattern. Your total cost with a 6% sales tax added is $18.55. What is the cost per

Anna35 [415]

Answer: The fabric costs $7.60 per yard.

Step-by-step explanation: First we can divide it by 106 then multiply it by 100 to get rid of the 6% sales tax, which now the cost of the stuff is $17.50.

Next, we subtract 8 from this to represent the clothing pattern cost. Now it is $9.50.

The last stap to this is to divide it by 1 1/4 to get the final cost per yard:

The fabric costs $7.60 per yard.

4 0

3 years ago

If a firm produces nothing which of the following costs will be zero?

matrenka [14]

In general when a firm produces nothing it still has to pay for the fixed costs while the variable costs are zero

3 0

4 years ago

Find derivative problem Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0

3 years ago

A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of

cestrela7 [59]

The amount of gas consumed by first and second car were 20 gallons and 15 gallons respectively.

Explanation

Suppose, $x$ gallons of gas were consumed by the first car.

As the total gas consumption in one week is 35 gallons, so the amount of gas consumed by second car will be: $(35-x)$ gallons.

The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 15 miles per gallon of gas.

So, the distance traveled by the first car in $x$ gallons of gas $=35x$ miles and the distance traveled by the second car in $(35-x)$ gallons of gas $=15(35-x)$ miles.

Given that, the two cars went a combined total of 925 miles. So, the equation will be.....

$35x+15(35-x)=925\\ \\ 35x+525-15x=925\\ \\ 20x=925-525=400\\ \\ x=\frac{400}{20}=20$

So, the amount of gas consumed by the first car is 20 gallons and the amount of gas consumed by the second car is: (35 - 20) = 15 gallons.

3 0

4 years ago