Answer:
1st, 3rd, 4th
Step-by-step explanation:
1st one: 43 x
multiply x by 43
7 x 43 = 301
7 x 43 = 258
10 x 43 = 430
3 x 43 = 129
4 x 43 = 172
(correct)
2nd one: 12x
multiply x by 12
2 x 12= 32
we know that 2 x 12 is 2 so this equation does not work
(incorrect)
3rd one: 202x
multiply x by 202
6 x 202 = 1212
4 x 202 = 808
10 x 202 = 2020
3 x 202 = 606
8 x 202 = 1616
(correct)
4th one: 13x
multiply x by 3
9 x 13 = 117
2 x 13 = 26
7 x 13 = 91
3 x 13 = 36
10 x 13 = 130
(correct)
All the numbers in the first equation have a common factor of 2. Removing that gives
.. x +4y = 6
making it easy to solve for x
.. x = 6 -4y
My choice would be to solve for x using the first equation.
_____
On second thought, it might actually be easier to solve either equation for 8y. That term then directly substitutes into the other equation (equivalent to adding the two equations).
.. 8y = 3x -11 . . . . . from the second equation
.. 2x +(3x -11) = 12 . . . substituting into the first equation
.. 5x = 23 . . . . . . . . . . collect terms, add 11 (what you would get by adding the equations in the first place)
.. x = 4.6
.. y = (3*4.6 -11)/8 = 0.35
EXPLANATION
Let's see the facts:
The scale is---> 14 milimeters ----> 5 meters
Width = 42 milimeters
Applying the unitary method, the actual width of the pool is:

The width of the pool is 15m
The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.
In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.
So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:

Similarly,

Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:

Answer:
could u put this in english