Answer:
x = -3
Step-by-step explanation:
The line parallel to x=8 is another vertical line:
x = constant
To make it go through a point with an x-coordinate of -3, the constant must be -3.
Your line is ...
x = -3
Answer:
D
Step-by-step explanation:
If y = log x is the basic function, let's see the transformation rule(s):
Then,
1. y = log (x-a) is the original shifted a units to the right.
2. y = log x + b is the original shifted b units up
Hence, from the equation, we can say that this graph is:
** 2 units shifted right (with respect to original), and
** 10 units shifted up (with respect to original)
<u><em>only, left or right shift affects vertical asymptotes.</em></u>
Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.
Answer choice D is right.
Answer:
Sorry this is late and I think this is right.
They are both parallel, they have the same slope, and do <em>not </em>intersect. If you were to draw a slope out for it, you would find this to be true.
For example: Say the question called for you to explain why there aren't any solutions to these system of inequalities:
<em>y < - 1/2x -3</em>
<em>y > 1/2x + 2</em>
<em>y= -x/2 -3</em> and <em>y= -x/2 + 2 </em>have the same exact slope, are parallel, and never intersect. The first line is 5 units below the second line when x = 0. Because the lines are parallel, it is always below the second line. The solutions of y < - x/2 -3 are the points in the plane below the first line. The solutions of y > 1/2 + 2 are points above the second line.
I hope this helps you. Good luck on whatever you're working on and stay safe! Please let me know if this helped you or didn't.
