Answer:
The volume of compacted trash is 328 ft³ .
Step-by-step explanation:
Given as :
The length of compacted trash = 10.25 feet
The width of the compacted trash = 8 feet
The height of the compacted trash = 4 feet
Let The volume of the trash = V ft³
The volume of compacted trash is given as the product of length width and height
So, V = length × width × height
or, V = 10.25 × 8 × 4 ft³
or, V = 328 ft³
Hence The volume of compacted trash is 328 ft³ . Answer
<span>323° in radians
= 323 x pi / 180
= 5.6
answer is
</span><span>B. 5.6</span>
Note that while the figure is made up of rectangle and parallelogram, then the area of this figure
1. The area of rectangle is
The vertices of rectangle are points A(-2,-2), B(0,-6), C(8,-2) and F(6,2). Then
Therefore,
2. The area of parallelogram can be calculated using formula
The base of parallelogram is segment CD with length
and the height has length 2 un. Then
3. Now
Round each number and then do what the problem asks you to do wether that be subtraction or addition.
8^2 and 9^2. Because 8 squared equals 64 and 9 squared equals 81
