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jonny [76]
3 years ago
10

Phils age is 7 years more than 1/5 times peters age. Also, 4 times phils age is 2 years less than twice peters age. If x is pete

rs age in years, identify the equation that represents this situtation and identify the solution to the equation
Mathematics
1 answer:
scoundrel [369]3 years ago
5 0
Answer: Peters age is 25 years old.

The two equations that can be written given the information are:
h = x/5 + 7   and    4h = 2x - 2
When x = Peter's age and h = Phil's age.

If we use substitution, we can come up with the equation:
4(x/5 + 7)= 2x - 2
4x/5 + 28 = 2x - 2 
4x + 140 = 10x - 10
150 = 6x
25 = x
Solving this for x, we give us that Peter's age is 25.
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7 0
3 years ago
Two smaller triangles have areas of 75m^2 and 12m^2. Which of the following is the ratio of the perimeter of the smaller triangl
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2:5
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Read 2 more answers
The coordinates of the endpoints of AB and CD are A(2,
Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

m= \frac{y_2-y_1}{x_2-x_1}

Formula to Find Distance between two points

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

mAB ( represents , Slope of AB )

1. mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}

2. mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}

3. mCD=\frac{5-2}{6-5}=\frac{3}{1}=3

4. AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

5. BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

mAC = mBC  , and C is common point , hence these three are collinear points  making a straight line whole slope is -\frac{1}{3}

mAB=-\frac{1}{3}

mCD=3

mAB \times mCD = -\frac{1}{3} \times 3 = -1

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0
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