4 years ago

Common factors for 15 and 27

Mathematics

1 answer:

ivanzaharov [21]4 years ago

3 0

Its 3. Because 5*3 is 15 and 9*3 is 27

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eimsori [14]

Answer:

solution given:

let's see only in a right-angled triangle Δ ACD.

AC=3 units

AD=5 units

since Δ ACD is a right-angled triangle. It satisfies Pythagoras law

$AD^{2}=AC^{2}+CD^{2}$

25=9+ $CD^2$

$CD^2$ =25-9=16

$CD=\sqrt{16} =4 units$

Now

Area of rectangle Δ ACD= $\frac{1}{2} CD*AC=\frac{1}{2}*4*3=6\: square \:units$

similarly,

$\frac{1}{2} AD*CE=6\: square \:units\\ 5*CE=6*2\\CE=\frac{12}{5}=2.4 units$

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Δ ACE is a right-angled triangle. It satisfies Pythagoras law.

$AC^{2}=AE^{2}+CE^{2}\\3^2=AE^2+2.4^2\\9-5.76=AE^2\\AE and BC=\sqrt{1.24} =1.11 units$

now

area of trapezoid=area ofΔACD+Area of ΔABC

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The circumference of the hub cap of a tire is 82.14 centimeters. Find the area of this hub cap. Use 3.14 for pi

earnstyle [38]

Answer:

Circumference = 2 * radius * 3.14

82.14 = 2*3.14 r

r= 82.14/6.28=13.079 cm.

So the area = 3.14 r^2

3.14*13.079^2

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Hope this helps :)

Step-by-step explanation:

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