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julsineya [31]
4 years ago
13

Common factors for 15 and 27

Mathematics
1 answer:
ivanzaharov [21]4 years ago
3 0
Its 3. Because 5*3 is 15 and 9*3 is 27
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The sum of two numbers is 35 . the smaller number is 19 less than the larger number. what are the numbers?
madreJ [45]
Let the smaller number be x and the larger be (x+19)
x+x+19=35
        2x=16
          x=8
x+19=27

the numbers are 8 and 27.
7 0
3 years ago
Chloe George
Ronch [10]

Answer:

ABC  = 27

DBC  = 56

Step-by-step explanation:

ABC + CBD = ABD

x+10 + 4x-12 = 83

Combine like terms

5x -2 = 83

Add 2 to each side

5x-2+2 = 83+2

5x = 85

Divide each side by 5

5x/5 = 85/5

x =17

ABC = x+10 = 17+10 = 27

DBC = 4x-12 = 4*17 -12 = 68-12 = 56

8 0
4 years ago
Read 2 more answers
Angle a is 11 times as large as its supplement angle b
Cerrena [4.2K]
Angle A is 165°, Angle B is 15°

5 0
4 years ago
A motorboat that travels with a speed of 20 km/hour in still water has traveled 20 km against the current and 180 km with the cu
Gala2k [10]
Recall your d = rt.  distance = rate * time.

let's say the speed of the current is "c".

keeping in mind that, when the boat is going against the current, the boat is not really going at 2kmh, but instead at " 20 - c ", because the current is subtracting speed from it.

Likewise when is going with the current, is going at a speed of " 20 + c ".

if the boat took say "t" hours on the way over, on the way back it took the slack from the whole 8 hours and "t", namely it took " 8 - t " hours.

\bf \begin{array}{lccclll}
&\stackrel{km}{distance}&\stackrel{kmh}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{against the current}&20&20-c&t\\
\textit{with the current}&180&20+c&8-t
\end{array}
\\\\\\
\begin{cases}
20=(20-c)(t)\implies \frac{20}{20-c}=t\\
180=(20+c)(8-\stackrel{\downarrow }{t})\\
--------------\\
180=(20+c)\left( 8- \stackrel{\downarrow }{\frac{20}{20-c}}\right)
\end{cases}
\\\\\\
180=(20+c)\left( \cfrac{(160-8c)-20}{20-c} \right)

\bf 180=(20+c)\left( \cfrac{140-8c}{20-c} \right)\implies 180(20-c)=(20+c)(140-8c)
\\\\\\
3600c-180c=2800-160c+140c-8c^2
\\\\\\
3600c-180c=2800-20c-8c^2
\\\\\\
3600c-180c-2800+20c+8c^2=0\implies 8c^2-160c+800=0
\\\\\\
c^2-20c+100=0\implies (c-10)(c-10)=0\implies \boxed{c=10}
8 0
3 years ago
What is the product of (2x2 + 5x - 3) and (3x +7)?
kicyunya [14]

Answer:

6x^3 + 29x^2 + 26x -21

Step-by-step explanation:

(2x^2 + 5x -3)(3x + 7) = 6x^3 + 14x^2 + 15x^2 + 35x - 9x -21

                                  = 6x^3 + 29x^2 + 26x -21

8 0
3 years ago
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