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igomit [66]
4 years ago
13

Which value make the equation 3x-6=36 true

Mathematics
2 answers:
elena-s [515]4 years ago
7 0

Answer:

x=14

Step-by-step explanation:

To solve, we need to isolate the variable (x)

3x-6=36

Add 6 to both sides

3x=42

Divide by 3 on both sides

x=14

14 is the value that make the equation true

Hope this helps! :)

Umnica [9.8K]4 years ago
5 0

Answer:

x=14

Step-by-step explanation:

To do this, we can solve the equation. We do that by isolating the variable.

Keep in mind, whatever operation you do to one side, you have to do to the other to ensure the equation is accurate.

3x-6=36

Add 6 to both sides to reverse -6.

3x=42

Divide both sides by 3 to reverse the multiplication being done to x.

x=14

Therefore, 14 makes the equation true.

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What different symbols do i use for at least at most exceeds no more than etc
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Answer:

yltkh

Step-by-step explanation:

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6 0
3 years ago
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An apartment complex on Ferenginar with 250 units currently has 223 occupants. The current rent for a unit is 892 slips of Gold-
Triss [41]

Answer:

Step-by-step explanation:

Given data

Total units = 250

Current occupants = 223

Rent per unit = 892 slips of Gold-Pressed latinum

Current rent = 892 x 223 =198,916 slips of Gold-Pressed latinum

After increase in the rent, then the rent function becomes

Let us conside 'y' is increased in amount of rent

Then occupants left will be [223 - y]

Rent = [892 + 2y][223 - y] = R[y]

To maximize rent =

\frac{dR}{dy}=0\\=2(223-y)-(892+2y)=0\\=446-2y-892-2y=0\\=-446-4y=0\\y=\frac{-446}{4}=-111.5

Since 'y' comes in negative, the owner must decrease his rent to maximixe profit.

Since there are only 250 units available;

y=-250+223=-27\\\\maximum \,profit =[892+2(-27)][223+27]\\=838 * 250\\=838\,for\,250\,units

Optimal rent - 838 slips of Gold-Pressed latinum

8 0
4 years ago
Assuming that the ship travels at a constant speed, what is its speed?
Ilia_Sergeevich [38]

Answer: S= d/p

Step-by-step explanation: Take the distance (d) divided by time (t) and you should have your answer

4 0
3 years ago
370 College freshmen were interviewed. 200 were registered for an Advanced Math class. 270 were registered for an English class
frozen [14]

Answer:

Step-by-step explanation:

To aid in understanding, draw three circles...

100 were registered for both Math and English.

50 were registered for both Sport and English but not Math.

70 were registered for Math, Sport, and English.

From here we will be able to calculate for those that signed up for only English class: Total number of students that signed up for english class

a. none signed up only for Maths (refer to attached document)

b. How many signed up for neither Math nor English meaning they signed up for only sports which is 70 from the venn diagram in the attachment.

c. How many signed up for an English class and at least one other class?

From the venn diagram:

we could have an English class and maths class - 100

we could also have an a English class and sports - 50

Thus total is 150.

d. What is the total fee for all the students enrolled in classes

From the diagram, 120 (english only and sport only) enrolled for only one class = 120 x $100 = $12,000

From the diagram, 180 (english and sport, maths and sport and english and maths) enrolled for two classes = 180 x $150 = $27,000

From the diagram, only 70 enrolled for the three classes = 70 x $200 = $14,000

Total fees = $12,000 + $27,000 + $14,000 = $53,000

5 0
4 years ago
12 2/5 x 3 1/6 pls help me
Maurinko [17]
1. Turn improper
12 \frac{2}{5}  =  \frac{62}{5}
3 \frac{1}{6}  =  \frac{19}{6}
2. set up the problem
\frac{62}{5}  \times  \frac{19}{6}
now multiple across and simplefy
3 0
3 years ago
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