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Helen [10]
3 years ago
10

I have never understood these. Help.

Mathematics
2 answers:
Reika [66]3 years ago
4 0

Answer:

5 sqrt(5)

Step-by-step explanation:

sqrt(125)

sqrt( 25*5)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(25) sqrt(5)

5 sqrt(5)

Mkey [24]3 years ago
3 0

Answer:

5√(5)

Step-by-step explanation:

Notice that 125 is 25×5

If you couldn't do it use the prime factorization.

Prime numbers are 2,3,5.....

125 isn't divisible by 2 and 3 so we'll go with 5.

● 125 ÷ 5 = 25

Againg 25 is divisible by 5

● 25÷5 = 5

5 is divisible by 5

● 5÷5=1

So 125= 5×5×5 = 5^2 × 5

● √(125)= √(5^2×5) = 5√(5)

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660

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a

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Which graph represents the function of f(x) = the quantity of 4 x squared minus 16, all over 2 x minus 4?
mestny [16]

Answer:

We are given with a function , f(x)=\frac{4x^2-16}{2x-4}

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f(x)=\frac{(2x)^2-4^2}{2x-4}

using identity, a² - b² = ( a - b )( a + b )

f(x)=\frac{(2x-4)(2x+4)}{2x-4}

f(x) = 2x + 4

Obtained function represent a straight line whose slope is 2 and y-intercept is 4

Let say, y = 2x + 4

then when x = 0 we get, y = 4

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7 0
4 years ago
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A boat sails directly toward a 250-m skyscraper that stands on the
bazaltina [42]

a) The value of  \theta as a function of "x" is \theta = tan^{-1}\frac{250}{x}

b) The rate of change of the angle with respect to x is -0.000308rad/m

Find the complete question and diagram attached

Form the right-angled triangle shown:

Adjacent side = x

Opposite side = 250m

angle of elevation  = \theta

Using the SOH CAH TOA identity

tan\theta = \frac{opposite}{hypotenuse} \\tan \theta = \frac{250}{x} \\\theta = tan^{-1}\frac{250}{x}

Hence the value of  \theta as a function of "x" is \theta = tan^{-1}\frac{250}{x}

b) If x = 450m

\theta = tan^{-1}\frac{250}{x}\\tan \theta = \frac{250}{x}\\

Differentiate both sides with respect to "x"

sec^2 \theta \frac{d\theta}{dx} = \frac{-250}{x^2}  \\ \frac{d\theta}{dx} =  \frac{1}{sec^2\theta} \times \frac{-250}{x^2}

Substitute x = 450m and \theta = 60^0 into the resulting expression to have:

\frac{d\theta}{dx} =  \frac{1}{sec^260^0} \times \frac{-250}{450^2}\\\frac{d\theta}{dx} =  (cos60)^2\times \frac{-250}{202,500}\\\frac{d\theta}{dx} = 0.5^2\times \frac{-250}{202,500}\\\frac{d\theta}{dx} =-0.000308

Hence the rate of change of the angle with respect to x is -0.000308rad/m

Learn more here: brainly.com/question/15580615

3 0
3 years ago
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