That is a vertical stretch by 2
here you go . i hope this helps
Answer:
4x²
Step-by-step explanation:
Your equation is 4x² - 6x² + 7x² - 20x² + 19x².
Since they all have the same variable, simply combine them all to find your answer.
4x² - 6x² + 7x² - 20x² + 19x²
-2x² + 7x² - 20x² + 19x²
5x² - 20x² + 19x²
-15x² + 19x²
4x²
Multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get
3x^2y.
Let us first define Hypotenuse Leg (HL) congruence theorem:
<em>If the hypotenuse and one leg of a right angle are congruent to the hypotenuse and one leg of the another triangle, then the triangles are congruent.</em>
Given ACB and DFE are right triangles.
To prove ΔACB ≅ ΔDFE:
In ΔACB and ΔDFE,
AC ≅ DF (one side)
∠ACB ≅ ∠DFE (right angles)
AB ≅ DE (hypotenuse)
∴ ΔACB ≅ ΔDFE by HL theorem.
