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3 years ago

How do I find the measure of angle d?

Mathematics

1 answer:

yan [13]3 years ago

7 0

D = 117
because angle 63 = angle 37+a because they are vertical angles,
therefore angle angle 37+a= angle b because they are corresponding angles
so if angle b=63 then angle d=117, so that together they equal 180, a supplementary angle.

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Write this fraction in the simplest form 15/25

Sladkaya [172]

15/25 Divididing numerator and denominator by 5 we get:

3 / 5

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4 years ago

Read 2 more answers

3. Find the product of 25x^2y and -6x²y3

mojhsa [17]

Answer:

-150 (x^2y+2)y³

Step-by-step explanation:

To Find the product of 25x^2y and -6x²y3.

(25x^2y) (-6x²y³)

= 25(-6) (x^2y+2) y³

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3 years ago

The number 160 is increased by 50%. The result is then decreased by 25%. What is the final number?

harkovskaia [24]

Answer:

Step-by-step explanation:

50%=.50

160×.50=80

160+80=240

25%=.25

240×.25=60

60 is the final number

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3 years ago

In ΔWXY, x = 680 inches, w = 900 inches and ∠W=157°. Find all possible values of ∠X, to the nearest degree.

ikadub [295]

Given:

In ΔWXY, x = 680 inches, w = 900 inches and ∠W=157°.

To find:

The all possible values of ∠X, to the nearest degree.

Solution:

Law of Sines:

$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$

For ΔWXY,

$\dfrac{w}{\sin W}=\dfrac{x}{\sin X}=\dfrac{y}{\sin Y}$

Now,

$\dfrac{w}{\sin W}=\dfrac{x}{\sin X}$

$\dfrac{900}{\sin (157^\circ)}=\dfrac{680}{\sin X}$

$900\sin X=680\sin (157^\circ)$

$\sin X=\dfrac{680}{900}\sin (157^\circ)$

$\sin X=0.295219$

$X=\sin^{-1}(0.295219)$

$X=17.17067$

$X\approx 17$

Therefore, the value of ∠X is 17 degrees.

5 0

3 years ago

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Ivan

Answer:

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4 0

2 years ago