Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
Step-by-step explanation:
the height is 80 m
hope that helps
Answer:
Step-by-step explanation:
Let the two numbers be 2x and 3x.
According to the question,
2x+3x=45
5x=45
x=45/5
x=9
so th required numbers are 18 and 27 as
2x=2*9=18
3x=3*9=27
Answer:
m<A = 30 degrees.
Step-by-step explanation:
m < C in triangle ABC = m < C in EDC so
x + 13 + 42 + x + 13 = 180
2x = 180 - 13 - 13 - 42
2x = 112
x = 56.
So m < C = 56+13 = 69.
m < B = m < D = 81
M < A = 180 - 69 - 81
= 180 - 150 = 30.
Log number 1 find catalog 5 - 4 = 1 . ( f .g ) 1 log = 0
