Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
I would solve it for B, but that's just what I think. So you would do -12 time -2 which is 24, then subtract 24 from both sides so that you would get B=-31
Is there a picture? there's not enough info
2/15 sorry if it’s wrong all I did was just divide both of them
The answer is 3p+6 gggghhnbhjjn
