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Tom [10]
3 years ago
10

Simplify the expression: 2√75+ √20

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer: 10\sqrt{3}+2\sqrt{5}

Step-by-step explanation:

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Two consecutive perfect squares have a difference of $99$. what is the value of the larger perfect square?
Fofino [41]

Answer:

2500

Step-by-step explanation:

Let the first square number be x^2 then the next square number is (x+1)^2.

The difference between these two consecutive numbers is 99.

This implies that:

(x+1)^2-x^2=99

We expand to get:

x^2+2x+1-x^2=99

Simplify:

2x=99-1

2x=98

Divide both sides by 2

x=49

Therefore the value of the larger perfect number is

(49+1)^2=50^2=2500.

6 0
3 years ago
Solve for g.<br> g/6 - -53 = 57
Mashcka [7]

Step-by-step explanation:

g/6 - -53 = 57

g/6 + 53 = 57

g/6 = 4

g = 4×6 = 24

5 0
2 years ago
Pls Help<br> I will mark as brainliest!!!!<br> which integer represents a golf score of 4 over par?
levacccp [35]

Answer:

Pls Help

I will mark as brainliest!!!!

which integer represents a golf score of 4 over par?

Step-by-step explanation:

I will mark as brainliest!!!!

which integer represents a golf score of 4 over par?Pls Help

I will mark as brainliest!!!!

which integer represents a golf score of 4 over par?

8 0
2 years ago
Read 2 more answers
Which set of angles will be complimentary
White raven [17]

∠1 + ∠3 + 90° = 180°

∠1 + ∠3 = 90°

∠3 = ∠4 (vertically opposite angles)

∠1 + ∠4 = 90°

Therefore, the answer is ∠1 + ∠4

3 0
3 years ago
Absolute value inequalities. 10-4|9y-10|&lt;-94
Ivahew [28]

Answer: \begin{bmatrix}\mathrm{Solution:}\:&\:y4\:\\ \:\mathrm{Decimal:}&\:y4\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:-\frac{16}{9}\right)\cup \left(4,\:\infty \:\right)\end{bmatrix}

Step-by-step explanation:

10-4\left|9y-10\right|

10-4\left|9y-10\right|-10

-4\left|9y-10\right|

\left(-4\left|9y-10\right|\right)\left(-1\right)>\left(-104\right)\left(-1\right)

4\left|9y-10\right|>104

\frac{4\left|9y-10\right|}{4}>\frac{104}{4}

\left|9y-10\right|>26

9y-1026

y4

5 0
3 years ago
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