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Olegator [25]
3 years ago
7

Please help me with questions 5, 6, and 7

Mathematics
1 answer:
never [62]3 years ago
4 0
Answer to problem 5 is A) WU = ZX. 
Notice how the angle U is between WU and VU. Similarly, angle X is beween ZX and XY
The order is very important. The angles must be between the two pairs of sides. 

-----------------

Answer to problem 6 is C) 15/17. 
Use the pythagorean theorem to find the hypotenuse AC to be 17 units. Then take the ratio of the adjacent and hypotenuse to get the answer.

------------------

Answer to problem 7 is choice C
Use the rule cos(90-x) = sin(x) where x = 72-a

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Answer: -5(3y+5)

Step-by-step explanation:

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3 years ago
Some parts of California are particularly earthquake- prone. Suppose that in one metropolitan area, 25% of all homeowners are in
aleksandrvk [35]

Answer:

a. Binomial random variable (n=4, p=0.25)

b. Attached.

c. X=1

Step-by-step explanation:

This can be modeled as a binomial random variable, with parameters n=4 (size of the sample) and p=0.25 (proportion of homeowners that are insured against earthquake damage).

a. The probability that X=k homeowners, from the sample of 4, have eartquake insurance is:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{4}{k} 0.25^{0}\cdot0.75^{4}

The sample space for X is {0,1,2,3,4}

The associated probabilties are:

P(x=0) = \dbinom{4}{0} p^{0}(1-p)^{4}=1*1*0.3164=0.3164\\\\\\P(x=1) = \dbinom{4}{1} p^{1}(1-p)^{3}=4*0.25*0.4219=0.4219\\\\\\P(x=2) = \dbinom{4}{2} p^{2}(1-p)^{2}=6*0.0625*0.5625=0.2109\\\\\\P(x=3) = \dbinom{4}{3} p^{3}(1-p)^{1}=4*0.0156*0.75=0.0469\\\\\\P(x=4) = \dbinom{4}{4} p^{4}(1-p)^{0}=1*0.0039*1=0.0039\\\\\\

b. The histogram is attached.

c. The most likely value for X is the expected value for X (E(X)).

Is calculated as:

E(X)=np=4\cdot0.25=1

6 0
3 years ago
All the songs all the figures except a _____ have to bases
serious [3.7K]

Answer:

Square pyramid

Step-by-step explanation:

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3 years ago
Sal recorded the number of crackers in each snack-sized package he opened. Which statement must be true according to the box plo
Marina CMI [18]

Answer:

The data is skewed, and the lowest number of crackers in a package was 7

Step-by-step explanation:

Hi,

First of all, since the question was incomplete due to the missing capture of the range shown on the box plot. I attached it for you so I could answer your question as well.

Taking into consideration the attached image's information, symmetric would be right down the middle, but it is not.

The image shows that it is <em>positively skewed with the lowest number being 7.</em>

7 0
4 years ago
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