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scoray [572]
3 years ago
7

How can i get better at maths

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0

by consentration at class and think maths is easy solve ur question and see u willl have what u need

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An electric utility company determines the monthly bill for a residential customer by adding an energy charge of 7.32 cents per
Sedaia [141]

Answer:

y(x) = 0.0732x + 17.32

Step-by-step explanation:

The equation for the monthly charge has the following format

y(x) = ax + b

In which y(x) is the cost in function of the number of kilowatt-hours used(x), a is the price of each killowatt hour and b is the fixed(base) charge.

Base charge of $17.32 per month.

This means that b = 17.32

charge of 7.32 cents per kilowatt-hour

Our answer is in dollars. Each dollar is 100 cents. So 7.32 cents is a = 0.0732

Write an equation for the monthly charge y in terms of x, the number of kilowatt-hours used.

y(x) = ax + b

y(x) = 0.0732x + 17.32

6 0
3 years ago
A boat on a river travels downstream between two points, 90 mi apart, in 1 h. The return trip against the current takes 2 1 2 h.
docker41 [41]

Answer:

A)63miles per hour.

B)27 miles per hour

Step-by-step explanation:

HERE IS THE COMPLETE QUESTION

boat on a river travels downstream between two points, 90 mi apart, in 1 h. The return trip against the current takes 2 1 2 h. What is the boat's speed (in still water)??b) How fast does the current in the river flow?

Let the speed of boat in still water = V(boat)

speed of current=V(current)

To calculate speed of boat downstream, we add speed of boat in still water and speed of current. This can be expressed as

[V(boat) +V(current)]

It was stated that it takes 1hour for the

boat to travels between two points of 90 mi apart downstream.

To calculate speed of boat against current, we will substact speed of current from speed of boat in still water. This can be expressed as

[V(boat) - V(current)]

and it was stated that it takes 2 1/2 for return trip against the Current

But we know but Speed= distance/time

Then if we input the stated values we have

V(boat) + V(current)]= 90/1 ---------eqn(1)

V(boat) - V(current) = 90/2.5----------eqn(2)

Adding the equations we have

V(boat) + V(current) + [V(boat) - V(current)]= 90/2.5 + 90/1

V(boat) + V(current) + V(boat) - V(current)]=90+36

2V(boat)= 126

V(boat)=63miles per hour.

Hence, Therefore, the speed of boat in still water is 63 miles per hour.

?b) How fast does the current in the river flow?

the speed of the current in the river, we can be calculated if we input V(boat)=63miles per hour. Into eqn(1)

V(boat) + V(current)]= 90/1

63+V(current)=90

V(current)= 27 miles per hour

Hence,Therefore, the speed of current is 27 miles per hour.

7 0
3 years ago
Am I correct? Please check the attachment.
Sergio039 [100]
Yes you are correct
6 0
3 years ago
84 is 75%, how much is 100%
Afina-wow [57]
La respuesta es 112, es una regla de tres simples
6 0
3 years ago
625^x=5<br><br> A-1/4<br> B1/4<br> C-4<br> D4
murzikaleks [220]
Take logs of both sides:-

ln 625^x = ln 5

x * ln 0.625 = ln 5

x = ln 5 / ln 625

x =  0.25 answer
5 0
3 years ago
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