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valentinak56 [21]
3 years ago
5

What is the answer to x/5+6=36

Mathematics
2 answers:
Lapatulllka [165]3 years ago
5 0
Okay, So We Need To First Look At This:
x/5 + 6 = 36.
So, We Need To Solve.
First, Subtract 6.
x/5 = 36 - 6
36 - 6 = 30
x/5 = 30
Now, Multiply.
x = 30 * 5
30 * 5 = 150
So:
X = 150
Arlecino [84]3 years ago
5 0
Let's solve the equation step-for-step.

x/5 + 6 = 36

Simplify - 1/5x + 6 = 36

Subtract 6 from both sides. 1/5x + 6 - 6 = 36 - 6

1/5x = 30

Multiply both sides by 5 - 5* (1/5x) = (5) * (30)

x = 150

Hope this helps! :D
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Given h(x) = x2 – 5x + 7, find the following.<br> a. h(2)<br> b.h(-5)<br> c. h(-8)
azamat

Answer:

Step-by-step explanation:

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h(x) = x² – 5x + 7

h(-2) = (-2)² – 5(-2) + 7 =4+10+7 =21

h(-5) = (-5)² – 5(-5) + 7= 25+25+7 =57

h(-8) = (-8)² – 5(-8) + 7 = 64+40+7=111

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2 years ago
If n = 37 cm and l = 12 cm, what is the length of m?
emmainna [20.7K]

<em> would say that the answer is </em><em>A. 25 cm</em><em> only because 37-12=25 and I don't necessarily know what the question is trying to ask.</em>

<em>Hope this Helps!<3</em>

6 0
3 years ago
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Find the number that we can place in the box, so that the resulting quadratic is the square of a binomial.
Arturiano [62]

We need a number to complete

(x+c)^2=x^2+2xc+c^2

Since we have

2xc=\dfrac{4}{5}x \iff 2c=\dfrac{4}{5}\iff c=\dfrac{4}{10}=\dfrac{2}{5}

And so the expanded square is

\left( x+\dfrac{2}{5}\right)^2=x^2+\dfrac{4}{5}x+\dfrac{4}{25}

6 0
3 years ago
A car insurance company has determined that 9% of all drivers were involved in a car accident last year. among 14 drivers living
andriy [413]

The probability of getting 3 or more who were involved in a car accident last year is 0.126.

Given 9% of the drivers were involved in a car accident last year.

We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.

We have to use binomial theorem which is as under:

nC_{r}p^{r} (1-p)^{n-r}

where p is the probability an r is the number of trials.

Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]

=1-{14C_{0}0.9^{0} (0.1)^{14} +14C_{1} (0.9)^{1} (0.1)^{13} +14C_{2} (0.9)^{2} (0.1)^{12}}

=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}

=1-{0.2670+0.3654+0.2358}

=1-0.8682

=0.1318

Among the options given the nearest is 0.126.

Hence the probability that 3 or more are involved in the accident is 0.126.

Learn more about probability at brainly.com/question/24756209

#SPJ4

7 0
1 year ago
Sammie competes in 14 chess matches. Of those matches, she wins 8. What percent of the matches did Sammie win?
weeeeeb [17]

Answer:

57.1428%

Step-by-step explanation:

8 divided by 14 = 0.57142857142 then turn it to a fraction which you move the period two times to the right thus the answer is

57.1428....

5 0
2 years ago
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