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faltersainse [42]
3 years ago
9

The city planning commission has been given a budget of 300,000 if the density of concrete is 150 lbs/ft3 determine if the cpc c

an afford to buy the bridge. The cost of concrete is 0.80/lb
Mathematics
1 answer:
Romashka [77]3 years ago
7 0

Answer:

Check Explanation

Step-by-step explanation:

The volume of concrete required to build the bridge is missing and should be provided.

In its absence, let us assign a letter to it.

Let the volume of concrete required to build the bridge be V ft³.

And we further assume that the concrete is the only major material needed to build the bridge for the sake of our question.

Density = (mass/volume)

Density = 150 lb/ft³

Mass = ?

Volume = V ft³

Mass = (Density) × (Volume)

Mass of concrete required = 150 × V = (150V) lb

Cost of concrete is 0.80 per lb

1 lb of concrete costs 0.80

150V of concrete will cost 150V × 0.80 = (120V) currency amount.

Now, depending on the value of V, we can now determine if the city planning commission (cpc) can afford the bridge.

If 120V > 300,000 budget, the cpc cannot afford the bridge, but if 300,000 budget > 120V, then the cpc can afford the bridge.

Hope this Helps!!!

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Step-by-step explanation:

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Read 2 more answers
Suppose that a standardized biology exam has a mean score of 80% correct, with a standard deviation of 3. The school administrat
NemiM [27]

Answer:

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.

This means that n = 65, \pi = 0.76

99% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964

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The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

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