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RideAnS [48]
3 years ago
7

In 2008 Melvin thought that he was making a sound investment by buying $100,000 worth of Alpha Biotechnology stock. Unfortunatel

y, his investment has depreciated, losing 13% of its current value each year.
Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0
The current value of an invested of $100, 000 that has lost a value of 13% will be:
current value in percent=100-13=87%
The value of $100,000 investment will be:
87/100*100000
=$87,000
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This week in school, there is a 75 percent probability of having a fire drill, a 50 percent probability of a tornado drill,
vova2212 [387]

Answer: A (edg2020)

     

8 0
3 years ago
The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of
love history [14]
Area of a trapezoid: [(top +bottom)*height]/2
suppose the length of one base is x, then the other base is 5x-19
[(x+5x-19)*18]/2=477
[6x-19]*18=954
6x-19=53
6x=72
x=12
The longer base is 5*12-19=41


5 0
3 years ago
Angel runs 4 miles per day.What is the relationship between the number of days and how many miles he has run?
forsale [732]
The answer is D. Ratio. When ever you see “per” another number it’s a ratio.
3 0
3 years ago
Use a graph in a (-2π, 2π, π/2) by (-3, 3, 1) viewing rectangle to complete the identity.
yaroslaw [1]

First, notice that:

2\tan (\frac{x}{2})=2\cdot(\pm\sqrt[]{\frac{1-cosx}{1+\cos x})}

And in the denominator we have:

1+\tan ^2(\frac{x}{2})=1+\frac{1-\cos x}{1+\cos x}=\frac{1+cosx+1-\cos x}{1+cosx}=\frac{2}{1+\cos x}

then, we have on the original expression:

\begin{gathered} \frac{2\tan(\frac{x}{2})}{1+\tan^2(\frac{x}{2})}=\frac{2\cdot\pm\sqrt[]{\frac{1-\cos x}{1+cosx}}}{\frac{2}{1+\cos x}}=\frac{2\cdot(\pm\sqrt[]{1-cosx})\cdot(1+\cos x)}{2\cdot(\sqrt[]{1+cosx})} \\ =(\sqrt[]{1-\cos x})\cdot(\sqrt[]{1+\cos x})=\sqrt[]{(1-\cos x)(1+\cos x)} \\ =\sqrt[]{1-\cos^2x}=\sqrt[]{\sin^2x}=\sin x \end{gathered}

therefore, the identity equals to sinx

8 0
1 year ago
What is the approximate angle measure for angle W in the triangle below?
Artyom0805 [142]
In this case we know the three sides of the triangle, then this is a SSS triangle (Side Side Side). To solve this case, first we must use the Law of Cosines, applied to the opposite side to the angle we want to find.
We want to find angle W, and its opposite side is XV, then we apply the Law of Cosines to the side XV:
XV^2=XW^2+WV^2-2(XW)(WV)cos W
Replacing the known values:
116^2=96^2+89^2-2(96)(89)cos W
Solving for W
13,456=9,216+7,921-17,088 cos W
13,456=17,137-17,088 cos W
13,456-17,137=17,137-17,088 cos W-17,137
-3,681=-17,088 cos W
(-3,681)/(-17,088)=(-17,088 cos W)/(-17,088)
0.215414326=cos W
cos W = 0.215414326

Solving for W:
W= cos^(-1) 0.215414326
Using the calculator:
W=77.56016397°
Rounded to one decimal place:
W=77.6°

Answer: Third option 77.6°
3 0
3 years ago
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