Find all relative extrema of the function. use the second derivative test where applicable. (if an answer does not exist, enter
dne.) f(x) = x2 + 3x − 1
1 answer:
The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at (-1.5, -3.25).
_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at (-1.5, -3.25).
_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
You might be interested in
Answer:
dy/dx = -1/
Step-by-step explanation:
y = 1/x
dy/dx = d/dx(1/x)
=> dy/dx = d/dx()
=> dy/dx = -
=> dy/dx = -1/
Answer: Our required probability is 0.3162.
Step-by-step explanation:
Since we have given that
n = 60
Probability of success =
Probability that at most 39 of these relays come from supplier A would be
Hence, our required probability is 0.3162.