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Mathematics

1 answer:

DiKsa [7]3 years ago

4 0

Answer:

The radius is 4.37 in approximately

Step-by-step explanation:

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How many inches in 7 miles?

alexandr402 [8]

Answer:

443520

Step-by-step explanation:

7 0

4 years ago

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A hemisphere fake stone made of clay has a diameter of 16 inches. The density of clay is 0.0035 pounds per cubic inch. The clay

Rufina [12.5K]

Answer:

$137.82

Step-by-step explanation:

The volume of a hemisphere stone is given by the volume of a half-sphere:

Volume = (2/3) * pi * radius^3

If the diameter is 16 inches, the radius is 16/2 = 8 inches, so the volume is:

Volume = (2/3) * pi * 8^3 = 1072.33 in3

We need a total of 8 stones, so the total volume is:

Total Volume = 8 * 1072.33 = 8578.64 in3

The density of clay is 0.0035 pounds per cubic inch, so the total weight of the 8 stones is:

Weight = Total Volume * density = 8578.63 * 0.0035 = 30.0252 pounds

Finally, if the price of each pound of clay if $4,59, the final price is:

Price = 30.0252 * 4.59 = $137.82

8 0

4 years ago

Suppose that you would like to buy a home priced at $200,000. You plan to make a payment of 10% of the purchase price and pay 1.

Elina [12.6K]

Answer:

see below

Step-by-step explanation:

When you must do the same tedious calculation several times with different numbers, it is convenient to let a spreadsheet program do it for you. Here, the spreadsheet function PMT( ) computes the payment amount for the given interest rate, number of payments, and loan amount.

The loan amount is 90% of the purchase price.

The total interest over the life of the loan is the sum of the payments less the original loan amount.

The total monthly payment is the sum of the loan payment and the monthly escrow amount, which is 1/12 of the annual escrow amount.

_____

Here, we computed the total of payments using the unrounded "exact" value of each payment. We take this to be a better approximation of the total amount repaid, since the last payment always has an adjustment for any over- or under-payment due to rounding.