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uysha [10]
2 years ago
12

What's 9 + (28 − 2) ÷ 0.2

Mathematics
1 answer:
tekilochka [14]2 years ago
6 0

Answer:i think is ((((139)))))

Step-by-step explanation:

I hope it helps you

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The ordered pairs (1, 1) , (2, 16) , (3, 81) , (4, 256) , and ( 5, 625) represent a function. What is a rule that represents thi
Artemon [7]

Answer:

C

Step-by-step explanation:

Note that each of the y- coordinates is the x- coordinate raised to the power of 4.

(1, 1) → y = 1^{4} = 1

(2, 16) → y = 2^{4} = 16

(3, 81) → y = 3^{4} = 81

(4, 256) → y = 4^{4} = 256

(5, 625) → y = 5^{4} = 625

Thus the rule is y = x^{4} → C

4 0
2 years ago
Read 2 more answers
What is -(2×7)+(4g×9a)
kotykmax [81]
I think its 162 but i dont know so hope this helps sorry if it dont
4 0
3 years ago
The mean life of a television set is 119119 months with a standard deviation of 1414 months. If a sample of 7474 televisions is
Pepsi [2]

Answer:

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 119, \sigma = 14, n = 74, s = \frac{14}{\sqrt{74}} = 1.6275

What is the probability that the sample mean would differ from the true mean by less than 1.11 months?

This is the pvalue of Z when X = 119 + 1.1 = 120.1 subtracted by the pvalue of Z when X = 119 - 1.1 = 117.9. So

X = 120.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{120.1 - 119}{1.6275}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 117.9

Z = \frac{X - \mu}{s}

Z = \frac{117.9 - 119}{1.6275}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the sample mean would differ from the true mean by less than 1.1 months

3 0
3 years ago
-2,-1,0,1 whichave pair of numbers has a sum of zero
Verizon [17]
-1+1=0. So your answer is -1 and 1
3 0
2 years ago
Select all of the expressions which show how to convert 2.5 yards into inches.
PIT_PIT [208]

Answer:

90

Step-by-step explanation:

4 0
2 years ago
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