Question

Moore's law says that the number of transistors in a dense integrated circuit increases by 41% every year.

Answer 1

The expression gives the number of transistors in a dense integrated circuit in 1979 is:

$y = 5000(1+0.41)^5\\\\or\\\\y = 5000(1.41)^5$

Solution:

The increasing function is given as:

$y = a(1+r)^t$

Where,

y is the future value

a is the initial value

r is the growth rate

t is the number of years

From given,

a = 5000

$r = 41 \% = \frac{41}{100} = 0.41$

t = 1974 to 1979 = 5 years

Substituting the values in formula,

$y = 5000(1+0.41)^5\\\\y = 5000(1.41)^5$

Thus the expression gives the number of transistors in a dense integrated circuit in 1979 is found

Answer 2

Answer:

432.34.234.32

Step-by-step explanation: