All categories

3 years ago

Elisa purchased 5 balls of yarn for $5.35 each and 9 jars of glue for $3.45 each. What was the total cost ?

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

8 0

5($5.35) + 9($3.45) = $57.80

Bond [772]3 years ago

8 0

5.35 times 5= 26.75
3.45 times 9= 31.05
Add:
31.05 + 26.75 = 57.80
Hope this helps!

You might be interested in

Radius= 4cm. find the area and diameter of the circle

Bezzdna [24]

<h3>given:</h3>

radius= 4 cm

the area and the diameter of the circle.

<h3>solution:</h3><h3>diameter:</h3>

$d = 2r$

$d = 2 \times 4$

$d = 8 \: cm$

therefore, the diameter of the circle is 8 centimeters.

$a = \pi {r}^{2}$

$a = \pi \times {4}^{2}$

$a = 50.26548 \: {cm}^{2}$

$a = 50.27 \: {cm}^{2}$

hence, the area of the circle is 50.27 square centimeters.

6 0

3 years ago

Read 2 more answers

Can i please get some help here its math

LiRa [457]

X is 9

12x + 17 = -1 + 14x
18 = 2x
x = 9

7 0

3 years ago

Read 2 more answers

17 is what percent of 34

Stels [109]

Answer:

50%

Step-by-step explanation:

17/34 = .50

3 0

4 years ago

Read 2 more answers

Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal

a_sh-v [17]

Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

$\dfrac{1}{x}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{1}{y + 49}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{y + 49 + y}{y^{2} + 49 y }$ = $\dfrac{1}{49}$

Or, 2 y + 49 = $\dfrac{y^{2}+49y }{19}$

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = $\frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, y = $\frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}$

Or, y = $\frac{- 1 \pm \sqrt{121+3724}}{2}$

or, y = $\frac{- 1 \pm \sqrt{3845}}{2}$

or, y = $\frac{- 1 \pm 62.008}{2}$

∴ y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0

3 years ago

How many solutions exist for the given equation? 12x+1=3(4x+1)-2

enyata [817]

I got All Real Numbers (infinite answers); what's your answer choices?

6 0

3 years ago

Read 2 more answers