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Rzqust [24]
3 years ago
6

I need help with this question.

Mathematics
1 answer:
Tom [10]3 years ago
7 0

Answer:

384

Step-by-step explanation:

BECAUSE I KNOW IT

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Rewrite in simplest radical form: x^4/5 / x^1/3 into a√x^b
mrs_skeptik [129]

Answer:

\sqrt[15]{x^7}

Step-by-step explanation:

If we have the expression

\frac{x^{\frac{4}{5}}}{x^{\frac{1}{3}}}, we have to think about exponent rules.

If we have a^b \div a^c, then the value will be equal to a^{b-c}.

So \frac{x^{\frac{4}{5}}}{x^{\frac{1}{3}}} simplified will be x^{\frac{4}{5} - \frac{1}{3}}

Converting \frac{4}{5} and \frac{1}{3} into fifteenths (lcm) gets us \frac{12}{15} - \frac{5}{15} = \frac{7}{15}.

We can convert x^{\frac{7}{15}} into a radical by taking the denominator root of x to the numerator.

\sqrt[15]{x^7}.

Hope this helped!

6 0
3 years ago
Stir-fry is tony's favorite food to cook, but it always makes a lot of smoke! Tony needs to know the volume of his kitchen so he
konstantin123 [22]

Answer:

Volume = 680 ft³

Step-by-step explanation:

Given

Floor Area = 85 ft²

Height = 8 ft

Required

Volume of the Kitchen

To solve this, it'll be assumed that Tony's kitchen has a regular shape.

Having said that, the volume of Tony's kitchen is calculated as thus.

Volume = Floor Area * Height.

Substitute the values of floor area and height

Volume = 85ft² * 8ft

Volume = 680 ft³

Hence, the volume of Tony's kitchen is 680ft³

4 0
3 years ago
A 3rd degree polynomial function whose graph crosses the horizontal axis more than once.
Leni [432]
There are millions of solutions I’d recommend going to desmos and putting in a polynomial to find out if it does
5 0
2 years ago
A cone shaped cup has a radius of 4 inches and a height of 6 inches. Which measurement is the closest to the volume in cubic inc
mihalych1998 [28]
7488in3 in direct form of the eqation is the biggest answer but put 554in3 if in the parlogical form
4 0
3 years ago
PLEASE HELP WILL GIVE BRANLIEST IF CORRECT
nevsk [136]

Answer:

1,500,000,000

Step-by-step explanation:

6 0
3 years ago
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