A price floor is set at $1.00, what is the state of the market and amount of

It is May 1. The quoted price of a bond with a 30/360 day count and 12% per annum coupon in the United States is 105. It has a f

larisa86 [58]

Answer: option A is the correct option.

Cash price = 106.00

Explanation:

Cash price = quoted price + accrued interest

CP = Qp + I ..........................(1)

Quoted price = 105

Accrued interest = ?

STEP1 : FIND INTEREST;

Because the interest is not compounded

Accrued Interest = PRT ..........(2)

P= principal ( the face value)

R = rate per annum

T= period

P= 100

Since the period of payment of the face value was from April 1 to October 1 that means the period is 180 days, that means the 12% rate per annum (360 days), should be 6% rate per halve annum (180 days).

Therefore;

R = 6%

Since rate is applied every 30 days of the period which is 30/360 for an annum. Our period is 180 that's means rate will be applied to 30/180.

Therefore;

T = 30/180

Therefore using equation 2

I = 100 × 6% × (30/180) = 1.00

Accrued interest= 1.00

STEP 2: FIND CASH PRICE

using equation 1

Cash price = 105 + 1.00 = 106.00

4 0

3 years ago

When John first starts his job, he rides the bus wherever he goes. However, after one year, John receives a promotion and a pay

vekshin1

Answer:

c. Inferior

Explanation:

Based on the information provided it can be said that this behavior would indicate that to John, a bus ride is an inferior good. This term by definition is a good whose demand decreases when consumer's income rises. Since John received an increased salary with his promotion, he is now able to afford to be able to drive instead of taking the bus. Therefore his demand for taking the bus has drastically decreased.

4 0

3 years ago

Record the following process costing transactions in the general journal:

Ne4ueva [31]

Answer:

a.

Raw Materials $9,300 (debit)

Account Payable $9,300 (credit)

b.

Assembly Department $4,300 (debit)

Finishing Department $2,400 (debit)

Raw Materials $6,700 (credit)

c.

WIP Inventory-Assembly $10,500 (debit)

Cash $10,500 (credit)

d.

Overheads $12,100 (debit)

Property taxes-plant: Payable $1, 800 (credit)

Utilities-plant : Payable $4, 800 (credit)

Insurance-plant : Payable, $1, 700 (credit)

Provision for Depreciation-plant, $3, 800 (credit)

e.

Work In Process - Assembly Department $7,600 (debit)

Direct labor, $5, 000 (credit)

Manufacturing overhead, $2, 600 (credit)

f.

Work In Process - Finishing Department $11,300 (debit)

Direct labor, $4,700 (credit)

Manufacturing overhead, $6,600 (credit)

g.

Finishing Department, $10,500 (debit)

Assembly Department $10,500 (credit)

h.

Finished Goods Inventory $15,600 (debit)

Finishing Department $15,600 (credit)

Explanation:

Manufacturing costs accumulate in the Work In Process Account of their respective departments.

When goods are transferred out of the Assembly Department to the Finishing Department, de-recognize the cost from Assembly Department (credit) and recognized the cost in Finishing Department (debit).

When cost of goods completed are transferred out of the Finishing Department into Finished Goods Inventory, we de-recognize the cost from Finishing Department and recognize it in the Finished Goods Inventory.

5 0

3 years ago

Maria is a hard-working college sophomore. One Sunday, she decides to work nonstop until she has answered 100 practice problems

sdas [7]

Answer:

The correct answers are:

i. The marginal, or additional, gain from Maria’s first hour of work, from 8:00 AM to 9:00 AM, is <u> 40 </u> problems.

ii. The marginal gain from Maria’s third hour of work, from 10:00 AM to 11:00 AM, is <u> 20 </u> problems

iii. 2 hours working on problems, 2 hours reading (c)

Explanation:

i. The marginal gain from 8:00 AM to 9:00 AM is calculated thus:

work done at 8:00 AM = 0 problems

Work done at 9:00 AM = 40 problems

Marginal gain = (Work done at 9:00 AM) - (work done at 8:00) = 40 - 0 = 40 problems

ii. work done at 10:00 AM = 70 problems

work done at 11:00 AM = 90 problems

Marginal gain = 90 - 70 = 20 problems

iii. To get the best exam score, the most number of problems possible in total must be answered within the 4-hour period, and this is determined as follows:

we are told that Maria gets tired as time progresses and the number of questions answered reduces we notice the following numbers of questions answered in each hour:

8:00 AM to 9:00 AM = 40 - 0 = 40 problems (hour 1)

9:00 AM to 10:00 AM = 70 - 40 = 30 problems (hour 2)

10:00 AM to 11:00 AM = 90 - 70 = 20 problems (hour 3)

11:00 AM to Noon = 100 - 90 = 10 problems (hour 4)

Also, we are told that;

1 hour of reading = 25 problems

Comparing the reading and solving problems, we see that the number of problems solved in hour-1 and hour-2 (40 and 30 respectively) are more than the equivalent number of problems solved in reading for 1 hour, while hour-3 and hour-4 (20 and 10 respectively), have lesser equivalent number of problems each, than reading for one hour. Therefore to make the most out of the 4 hours, Maria will spend the first 2 hours solving problems and the next two hours reading, giving a total of: 40 + 30 + 25 + 25 = 120 problems solved.

4 0

3 years ago

g If the beginning work in process includes 200 units that are 20% complete with respect to conversion and 30% complete with res

Temka [501]

Answer:

1,140 units

Explanation:

Note : The question requires us to use the weighted-average method. This method focuses on equivalent units of completed units and units still in process only.

Step 1 : Determine units completed and transferred

Units Completed = Beginning units + Units Started - Ending units

= 200 + 1,000 - 100

= 1,100 units

Step 2 : Calculate equivalent units of production with respect to conversion costs

Completed and transferred (1,100 x 100%) 1,100

Ending units (100 x 40%) 40

Total equivalent units of conversion costs 1,140

thus,

the equivalent units of productions for the period (using the weighted-average method) for conversion is 1,140 units.

7 0

3 years ago