The standard eqn of a parabola in vertex form is y-k = a(x-h)^2, where (h,k) is the vertex. There are a good number of steps involved. I don't think it wise not to "show work." I cannot answer this question without going through all those steps.
However, there's an easier way to find the vertex. Identify the coefficients a, b and c:
a= -4, b= -3 and c = 1
Then the x-coord. of the vertex is x = -b / (2a). Subst. -3 for b and -4 for a and simplify. x = ??
Then find the y-coord. of the vertex by subbing your result, above, into the original equation.
Write the vertex as (h,k).
Once you have this vertex, you can find the equation in vertex form as follows:
Start with the general form y-k = a(x-h)^2, where (h,k) is the vertex.
You've already found the vertex (h,k). Subst. h and k into the general form, above. Then only the coefficient "a" remains undefined.
Answer: 9.6 units
<u>Step-by-step explanation:</u>
The formula for the length of a diagonal (d) for a rectangular prism given length (L), width (w), and height (h) is: d² = L² + w² + h²
Given: L = 8, w = 2, h = 5
d² = 8² + 2² + 5²
d² = 64 + 4 + 25
d² = 93
√d² = √93
d = 9.6
Answer:
3 will be the first piece
6 will be the second piece
21 will be the second piece
First u multipl 3 times 3 then 9 times 4 I think which is 36
Answer:
m∠1 = 67
Step-by-step explanation:
