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vovangra [49]
4 years ago
10

Rewrite the equation y^2 – 4y – 2x – 4 = 0 in standard form.

Mathematics
1 answer:
patriot [66]4 years ago
8 0

y² - 4y - 2x - 4 = 0

<u>            +2x +4 </u>   <u>+2x + 4 </u>

y² - 4y              = 2x + 4

<u>             +4    </u>      <u>       +4 </u>      

 (y - 2)²          = 2x + 8

<u>              -8   </u>      <u>      -8 </u>

 (y - 2)²  - 8   = 2x

\frac{(y - 2)^{2}}{2} - \frac{8}{2} = \frac{2x}{2}

\frac{1}{2}(y - 2)² - 4 = x

x = \frac{1}{2}(y - 2)² - 4

<em>Note: this is a parabola whose axis of symmetry is y = 2 and vertex is (-4, 2)</em>

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