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4 years ago

Rewrite the equation y^2 – 4y – 2x – 4 = 0 in standard form.

Mathematics

1 answer:

patriot [66]4 years ago

8 0

y² - 4y - 2x - 4 = 0

+2x +4 +2x + 4

y² - 4y = 2x + 4

+4 +4

(y - 2)² = 2x + 8

-8 -8

(y - 2)² - 8 = 2x

$\frac{(y - 2)^{2}}{2} - \frac{8}{2} = \frac{2x}{2}$

$\frac{1}{2}$ (y - 2)² - 4 = x

x = $\frac{1}{2}$ (y - 2)² - 4

Note: this is a parabola whose axis of symmetry is y = 2 and vertex is (-4, 2)

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