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igomit [66]
3 years ago
14

What is the 8th term in a geometric sequence where the first term is equal to 4 and the common ration is 2?

Mathematics
1 answer:
DochEvi [55]3 years ago
5 0

Answer:

512

Step-by-step explanation:

1st term =a

common ratio = r

a*r with the exponent n-1

a=4    r=2 n=8

8th term    4*(2 at the seventh power)= 512

OR

1st term  :4

2nd term = 4*2=8

3rd term 8*2=16

4th term  12*2=32...............8th term 256*2=512

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Read 2 more answers
Round each whole number to the given place value.
Kazeer [188]

We have to round each whole number to the given place value.

We have to round the number 437 to the tens place.

Since the digit at the tens place is 3.

Since the digit at its previous place that is ones place is '7' which is greater than 5.

Therefore, we can round the number 437 to 440.

Now, consider the another number 64,328, we have to round this number to the nearest ten thousand place.

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4 0
4 years ago
a student says that if 5x^2 = 20, then x must be equal to 2. do u agre or disagree with the student? justify your answer.​
inna [77]

Answer:

The student is correct.

Step-by-step explanation:

Given that 5x² = 20:

It is true that the value of x = 2 because 2² = 4, and when you multiply 4 with 5, you'll get a product of 20:

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Therefore, the student is correct that x = 2.

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2 years ago
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On which one do you need help with?
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