12cx+6yc pls mark as brainliest
Answer- KG⎯∥JH⎯
the given figure is a trapezium in which CF||DE
Reflection of figure CDEF and shifting it by 3 units does not change the shape of the figure but changes only its position in the x-y plane.
so, the shape of the figure GHJK will be same as that of CDEF.
so sides, KG⎯∥JH⎯
Find common denominators. 10 is the common denominator. Multiply 2 to numerator and denominator of -3/5
(-3/5)(2/2) = -6/10
x + 1/10 = -6/10
Isolate the x. Subtract 1/10 from both sides
x + 1/10 (-1/10) = -6/10 (-1/10)
x = -6/10 - 1/10
x = -7/10
-7/10 is your answer for x
hope this helps
Answer:
pay attention and do what your supposed to do and you'll be fine also dont pick the wrong group of friends.
Step-by-step explanation:
please mark brainliest... <3
The vertex of this parabola is at (3,-2). When the x-value is 4, the y-value is 3: (4,3) is a point on the parabola. Let's use the standard equation of a parabola in vertex form:
y-k = a(x-h)^2, where (h,k) is the vertex (here (3,-2)) and (x,y): (4,3) is another point on the parabola. Since (3,-2) is the lowest point of the parabola, and (4,3) is thus higher up, we know that the parabola opens up.
Substituting the given info into the equation y-k = a(x-h)^2, we get:
3-[-2] = a(4-3)^2, or 5 = a(1)^2. Thus, a = 5, and the equation of the parabola is
y+2 = 5(x-3)^2 The coefficient of the x^2 term is thus 5.
