Question

Select the exclusion that fits best with this problem.

Answer 1

Answer:

$\frac{1}{2y-2y^2}, y\neq 1$

Step-by-step explanation:

observe by factorization and cancelation

$\frac{y^2+y+1}{-2y(y^3-1)}=\frac{y^2+y+1}{-2y(y-1)(y^2+y+1)}\\=\frac{1}{-2y(y-1)}\\=\frac{1}{2y-y^2}$