The correction of thermal expansion per tape length, if the temperature at the time of measurements is 25°c and the pull exerted is 150N is 4.67 ×10 ⁻³m.
Thermal expansion is the tendency of remembering to change in form, volume, and region in response to an alternate in temperature. Temperature is a monotonic characteristic of the common molecular kinetic power of a substance.
Given,
Length of steel tape = 30m
Temperature at standardization = 15°C
The temperature at the time of measurement = 25°C
Standardized pull (Po) = 80N
Pull exerted (Pm) = 150N
Young modulus of elasticity = E = E= 2X10^5 N/mm2
Coefficient of thermal expansion = 211.2x10^6c°
Cross-sectional area of tape = 8 mm²
For temperature correction Cm = (Tm - T₀)αL₀
Putting α = ( 25 - 15 ) × 11.2 × 10⁻⁶ × 30
Cm = 3.36 × 10⁻³ m
For full correction ;
C pull = (Pm - Po ) × Lo
Putting value'
C pull = (150 - 80) × 30 × 1000 /8 ×2 × 10⁵
C pull = 1.31 × 10 ⁻³
Total correction = 3.36 × 10⁻³ m + 1.31 × 10 ⁻³
Total correction = 4.67 ×10 ⁻³
Learn more about thermal expansion here:-brainly.com/question/1166774
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hope this helps -Kaden
