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3 years ago

How do you solve this?

Mathematics

1 answer:

posledela3 years ago

4 0

Notice that the given info consists of boundary lines for an area in the xy plane. We are interested ONLY in values of x and y that are 0 or greater (positive). Graph 5x + 3y $\leq$ 37 and 3x + 5y less than or equal to 35.

Find the points of intersection of all four straight lines (including the x- and y-axes). There will be 4 such points (incl. the origin).

Next, evaluate the objective function 2x + 14y at each of these 4 points. Which of the four results is the largest? the smallest? Label them as 'maximum' and 'minimum.'

Questions? Just comment on this discussion.

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PLZ help solve !!!!!!!

Ivahew [28]

37 I think I’m not sure just saying a random number don’t trust me I just needed the points

4 0

3 years ago

I need help with 1 and 2 please :(

saveliy_v [14]

1 equals 0.3
2 equals 1.25

6 0

3 years ago

Read 2 more answers

The time between arrivals of customers at the drive-up window of a bank follows an exponential probability distribution with a m

castortr0y [4]

Answer:

a) 50.34% probability that the arrival time between customers will be 7 minutes or less.

b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 10 minutes:

This means that $m = 10, \mu = \frac{1}{10} = 0.1$

A. What is the probability that the arrival time between customers will be 7 minutes or less?

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)$

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

$P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592$

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442$

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

3 0

3 years ago

Find a_4 and a_n for the arithmetic sequence. a_6= -15, a_8= -7 <br> .

kiruha [24]

Sueinskwkakoqoqoqowowiiwiwiwiwiw

8 0

2 years ago

An elevator starts on the 100th floor. It descends 4 floors every 10 seconds. At what floor will the elevator be 60 seconds afte

Artyom0805 [142]

So is 4 floors / 10 seconds
If you have 60 seconds you can multiple 10 by 6 because 10×6=60
so you also have to multiple 4 by 6
4×6=24
and because it's descending it's 100-24= 76

8 0

3 years ago

Read 2 more answers