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luda_lava [24]
3 years ago
8

How do you solve this?

Mathematics
1 answer:
posledela3 years ago
4 0
Notice that the given info consists of boundary lines for an area in the xy plane.  We are interested ONLY in values of x and y that are 0 or greater (positive).  Graph 5x + 3y \leq 37 and 3x + 5y less than or equal to 35.

Find the points of intersection of all four straight lines (including the x- and y-axes).  There will be 4 such points (incl. the origin).

Next, evaluate the objective function 2x + 14y at each of these 4 points.  Which of the four results is the largest?  the smallest?  Label them as 'maximum' and 'minimum.'

Questions?  Just comment on this discussion.

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PLZ help solve !!!!!!!
Ivahew [28]
37 I think I’m not sure just saying a random number don’t trust me I just needed the points
4 0
3 years ago
I need help with 1 and 2 please :(
saveliy_v [14]
1 equals 0.3 
2 equals 1.25

6 0
3 years ago
Read 2 more answers
The time between arrivals of customers at the drive-up window of a bank follows an exponential probability distribution with a m
castortr0y [4]

Answer:

a) 50.34% probability that the arrival time between customers will be 7 minutes or less.

b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 10 minutes:

This means that m = 10, \mu = \frac{1}{10} = 0.1

A. What is the probability that the arrival time between customers will be 7 minutes or less?

P(X \leq x) = 1 - e^{-\mu x}

P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)

P(X \leq x) = 1 - e^{-\mu x}

P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034

P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592

P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

3 0
3 years ago
Find a_4 and a_n for the arithmetic sequence. a_6= -15, a_8= -7 <br> .
kiruha [24]
Sueinskwkakoqoqoqowowiiwiwiwiwiw
8 0
2 years ago
An elevator starts on the 100th floor. It descends 4 floors every 10 seconds. At what floor will the elevator be 60 seconds afte
Artyom0805 [142]
So is 4 floors / 10 seconds
If you have 60 seconds you can multiple 10 by 6 because 10×6=60
so you also have to multiple 4 by 6
4×6=24
and because it's descending it's 100-24= 76
8 0
3 years ago
Read 2 more answers
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