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3 years ago

Evaluate −6 − (−3). (1 point)

Mathematics

1 answer:

Nady [450]3 years ago

4 0

The answer is -3.

-6 - (-3) —> 2 negatives makes a positive
-6 + 3 = -3

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Carly is buying deli meat for her lunches this week. Turkey is on sale for $5.80 per pound. If Carly buys 1.25 pounds of turkey,

alisha [4.7K]

Answer:

Carly will have to spend $7.25

Step-by-step explanation:

We know that:

1 pound of turkey = $5.80

To find how much 1.25 pounds of turkey will cost, multiply:

5.80 x 1.25 = 7.25

Therefore, 1.25 pounds of turkey will cost $7.25

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A particular isotope has a half-life of 74 days. If you start with 1 kilogram of this isotope, how much will remain after 150

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$\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}$

$\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}$

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3 years ago

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mote1985 [20]

Answer:

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Step-by-step explanation:

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